Generally electron affinity goes up as you go from left to right across the Periodic Table, and decreases as you go down a column. However, fluorine is an exception -- and the element with the highest electron affinity is chlorine.
(Note that the most electronegative element is fluorine however; 'electronegativity' is not exactly the same as 'electron affinity'.)
Electronegativity is the ability of an atom in a molecule to draw bonding electrons to itself
Electron affinity is a measure of the energy change when an electron is added to a neutral atom to form a negative ion.
The reason that the electron affinity is not as high as might otherwise be predicted for fluorine, is that it is an extremely small atom, and so it's electron density is very high. Adding an additional electron is therefore not quite as favorable as for an element like chlorine where the electron density is slightly lower (due to electron-electron repulsion between the added electron and the other electrons in the electron cloud).
Iodine gains electrons to form an anion (I-) through the process of reduction, as it has the ability to accept an electron to achieve a stable electron configuration.
In iodine (I), the electron configuration is [Kr]5s²4d¹⁰5p⁵. This means that there are 10 electrons in the 4d orbital.
The ion would be Iodine (I). It has 53 protons and normally has 53 electrons, so if it gains an extra electron, it becomes a negatively charged ion with 54 electrons.
Iodine has 53 protons, while silver has 47 protons.
The beaker is more concentrated in iodine because it contains a higher amount of iodine compared to the baggie.
Yes. It's true. Chlorine has the highest electron affinity, then Fluorine, Bromine and Iodine
Bromine has a higher electron affinity than iodine. This is because bromine has a smaller atomic size, resulting in a stronger attraction for electrons compared to iodine.
According to Zumdahl, Group 7A elements (halogens) follow the expected behavior or periodicity as you follow top to bottom. The numbers (top to bottom) are getting closer to 0, so they are decreasing in electron affinity. Bromine has a higher negative # therefore it is a higher electron affinity.---papajohn
The other members of group 17, the halogens. Specifically chlorine
HONClBrIF Hydrogen Oxygen Clorine Bromine Iodine Flourine
+/- 1 (5,7) are the listed oxidation states, but many of these elements that have many electron shells can reach deep into their valance shells for greater oxidation states due to a possibility of electron shielding.
Iodine's electron configuration is 2, 8, 18, 18, 7; bromine's is 2, 8, 18, 7. At the simplest level of modelling there is one more electron shell occupying space in an iodine atom than in one of bromine.
Barium loses electrons to obtain a stable octet, like any other metal.
No, iodine has four electron shells, marked as "K", "L", "M", and "N". The number of electron shells is determined by the electron configuration of an element.
Iodine has one unpaired electron in its ground state.
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Iodine gains one electron to achieve a noble gas electron configuration. Its electron configuration is [Kr]5s²4d¹⁰5p⁵, and by gaining one electron, it attains the stable configuration of [Kr]5s²4d¹⁰5p⁶, which is similar to the noble gas xenon.