Calculus

x= 1.67(rnd)

5= -4+3x+4

5- -4= 9

9=3x+4

9-4=5

5=3x

x= 1.67(rnd)

90x

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The equation you have given, y + 2 = 7, does not describe a line, it describes the number 5. You would not graph a single number, there is nothing to graph.

No, these are of different values.

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It is not clear whether you are interested in

sqrt(1 - x2) or sqrt(1 + x2)

It is 56/9*sqrt(42) which is approx 40.32 square units.

1.249 radians from the horizontal.

I suspect the answer depends on the value of t.

x+y = 6

-x+3y = -2

Add the equations:-

4y = 4

Divide both sides by 4:-

y = 1

So by substitution x = 5 and y = 1

It just goes to sleep it does not go anywhere i hope that helped

FALSE

9.64

yes i really do agree with you its awsome

1,760 × 8,800 = 15,488,000. You can easily arrive at this result, if you like, through mental calculations: First, of all, 1760 × 8800 = 176 × 88 × 1,000 = 2 × 88 × 88 × 1,000. Now, what is a painless way to find 88² ? 88² - 12² = (88 - 12)(88 + 12) = 76 × 100 = 7,600. Thus, 88² = 7,600 + 12² = 7,744. Now, double 7,744, and add 3 zeroes. Magically, you get 15,488,000, which is your answer. After all, 2(7,500 + 244) = 15,000 + 488. You can easily confirm this with your calculator.

Answer: 222236 km² = 85,805.8 mi²

3+2 is a pair cause it has equled to 6.

x^2 - 2x = 0

x(x - 2) = 0

x = 0 or x = 2

No, not always. For example, sqrt(2) is irrational (1.41421...), but sqrt(2)/sqrt(2) = 1. 1 is a rational number. Similarly, 2*sqrt(2) is irrational (2.82842...), but sqrt(2)/(2*sqrt(2)) = 1/2. 1/2 is a rational number.

I think there is a problem with the equation, because the area cannot be in liters,I think that it should be the volume which is 0.7538 instead of the area. can you make sure that it is correct?

x = 392 I found this answer on a table that matches the first six numbers you have given.

Assuming I read this right:

66000 x 1.011254t = 200000

1.011254t = 200000 / 66000 = 100/33

taking logs of both sides

4t log 1.01125 = log(100/33)

t = log(100/33) / (4 x log 1.01125)

Logs used can be any base, but must be the same base:

t ~= 24.77527