Calculus

A set of numbers can have only 1 greatest common factor.

GCF(24, 32) = 8

f(t) = t^2 + t

F(t) = (1/3)t^3 + (1/2)t^2 ---- g(x) = 2sin(2x)

G(x) = -cos(2x)

---- h(x) = 5x

H(x) = (5/2)x^2

---- p(x) = cos(x) + cos(2x)

P(x) = sin(x) + (1/2)sin(2x)

---- q(x) = e^x

Q(x) = e^x

if you mean 5 x (10-2) then the answer is

.05

3/14 = X/84 Cross multiply the proportion: 14X = 252 X = 252/14 = 18.

Start on the left-hand side.

cos(x) + tan(x)sin(x)

Put tan(x) in terms of sin(x) and cos(x).

cos(x) + [sin(x)/cos(x)]sin(x)

Multiply.

cos(x) + sin2(x)/cos(x)

Make the denominators equal.

cos2(x)/cos(x) + sin2(x)/cos(x)

Add.

[cos2(x) + sin2(x)]/cos(x)

Use the Pythagorean Theorem to simplify.

1/cos(x)

Since 1/cos(x) is the same as sec(x)- the right-hand side- the proof is complete.

Sqroot x > x if x<1.

In real-world situations, the best that you can do is approximate using numerical methods. For instance, you could take an aerial photograph of the region, overlay a grid, and then use methods such as "The trapezoid rule" or "Simpson's rule". Any calculus text should cover how to use these and you can also find a description of these methods at:

http://en.wikipedia.org/wiki/Trapezoidal_rule

http://en.wikipedia.org/wiki/Simpson%27s_rule

If, however, it is a math problem and you are given functions of the curves (or rivers), then you just integrate the difference (in absolute value) of the two functions. For instance, if we have the curves f and g on [a,b], and f is greater than or equal to g on the interval, then we just integrate f-g over [a,b].

2(1 - 3x + 6) = -x

14 - 6x = -x

14 - 6x + 6x = -x + 6x

14 = 5x

14/5 =5x/5

14/5 = x

...If you are a human in the typical mass range, you can walk on Mars no problem...in fact if you're somewhat heavy set, you'll notice it is significantly easier to walk on Mars because its gravity is less than Earth's... and x is the twenty-fourth letter of the English alphabet. It makes a "ks" sound.

Jokes aside, there could be a rather complex physics question hidden in there. At a large enough volume to mass ratio, the force of gravity pulling you down will no longer be sufficient to balance the relatively small buoyant force exerted by the thin Martian atmosphere. Assuming no wind, which is ludicrous because it's almost always windy on Mars, you would have to have a density equal to or greater than that of the Martian atmosphere in order to walk on the planet. In other words, it's not a question of 'weight', it's how much matter you have packed into how much space....still don't know what you mean by x though. Sorry!

-2

3.14

-9

7

3

25

hyperbola

xy=total cost

x=1.875

When calculating mean, you sum every number in some data set and divide by how many numbers are in the set.

For every zero added to the data, the sum doesn't change but the number which you divide the sum by increases by one.

For example, if your homework grades in a class are:

82, 76, 90, 85, 92

Your mean homework grade then is

(82 + 76 + 90 + 85 + 92) / 5 = 425 / 5 = 85

Say you forget to do your next homework assignment, so you get a zero. To calculate your new mean grade, instead of adding up the numbers again, just increase the denominator by one:

425 / (5 + 1) = 425 / 6 = about 71

Three US quarts is about 0.002839059 cm3

pooo000ooo000ooo000ooo000ooo000ooo000ooo000ppp

well y=.04x is most likey a linear equation with the .04 as the slope of the line and there is no y intercept or the y intercept is 0

factor x2-14x+46 What two numbers multiply to give 46, and (since the 14 is negative) are 14 apart?

Well, 46 only factors into [1 2 23 46], so there are no integer answers.

This calls for the quadratic formula

(-b±√(b2-4ab))/2a

(14±√(196-184)/2

(14+√(12))/2 and (14-√(12))/2

(14+3.464)/2 and (14-3.464)/2

17.464/2 and 10.536/2

8.7321 and 5.2679 are both approximations of the answers. ■