Probability

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I want Jntu cse 2-1 on-line bits in probability and statistics http://www.worldwebsites8.blogspot.com/

it depends on if you can ride a unicycle dressed as Hitler with one shoe and no sock on the other foot and one hand tied behind your back with a fish being juggled by the other hand and your tongue.

I'm not sure but that is the theory of everything ,still being founded

On a single toss of a six-sided die. The chance of rolling a one is 1/6, and the chance of not rolling a one is (1 - 1/6 = 5/6), or 83.333 %

Neither. The marble has higher density than breadcrumbs or croutons, so it will sink, not rise.

Yes.

It depends to what depth. One cubic INCH will cover 400 square feet in sandstone dust but it will be only 0.00002 inches deep!

Any way that you want to.

2 out of 4 chance

hey

Hypothesis =)

If Roberto has 200 coins and distributes them in such a way that each friend gets at least one coin, and no two friends get the same number of coins, the largest number of friends Roberto could have is 19.

This is a simple triangular function of a number.

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19 = 190

At that point, Roberto only has 10 coins left, and he can not give them to anyone else without duplicating the amount two friends get.

1 in 6

H. P. Lovecraft was born on August 20, 1890.

It is: 1/2

50%

It is not!

There are 26 letters in the English alphabet, of which 5 are vowels (a, e, i, o, u). Since each card is identical and there are 26 cards in the box, the probability of selecting any one card is 1/26.

To find the probability of selecting two cards with vowels printed, we need to use the concept of conditional probability. The probability of selecting a vowel on the first draw is 5/26, since there are 5 vowels in the box. After the first card is selected and not replaced, there are only 25 cards left in the box, of which 4 are vowels (since one vowel has already been selected). Therefore, the probability of selecting a vowel on the second draw, given that a vowel was selected on the first draw, is 4/25.

To find the probability of both events occurring (i.e., selecting two cards with vowels printed), we need to multiply the probabilities of each event together, since they are independent:

P(selecting a vowel on the first draw) x P(selecting a vowel on the second draw, given that a vowel was selected on the first draw) = (5/26) x (4/25)

Simplifying this expression, we get:

(5/26) x (4/25) = 20/650 = 2/65

Therefore, the probability of selecting two cards with vowels printed is 2/65

Bascal paul

gives a standardized unit that tells how far away each measurement is from the mean

3, Indian Head cent, Indian Head nickel, Indian Head Gold half eagle

1/6 x 1/6 x 1/6 = 1/216

for what?

It can be, but it need not be.