Calculus

2x2 + 7x = 0 => x(2x+7)=0

so x = 0 or 2x+7 = 0

ie x = 0 or x = -7/2

3x2 has x, x2 , and 3 as factors. 2x-5 does not have any of those as factors. So the greatest common factor is 1. If you were adding rational expressions with those two expressions in the denominator, you would need to multiply them together to find the least common denominator.

76 is composite.

-18

(3, 2)

3139.5

y(z+x) + 4(x+z)

If the hole is empty, zero. If it is filled completely with water, 16*16*16 = 4096 units³.

Arcsin

7

It is 0 cuz there is no 5.

They both measure a linear relationship between two variables.

X + y = 8

x - y = 6

add equations to eliminate y

2x = 14

x = 7

substitute

7 + y = 8

y = 1

If you mean: x/6 +11 = 20 then the value of x is 54

Check: 54/6 +11 = 20

there is 1000 mb in a gig I believe

Subtract 9 from each side. ( subtraction; both sides )

X + 9 = 20

X + 9 - 9 = 20 - 9

X = 11

-----------------check in original equation

11 + 9 = 20

20 = 20

checks

There is no slope, because the equation as provided was in one variable only, x, no y. Sorry. Please restate the question.

You might need to elaborate more i am not sure what you mean by concident, but if you mean consistent as in is the graph consistent or inconsistent and dependant or independant . then I can help

we have 3y=6x-3

which equals y=2x-1

so m= 2 and b=-1

and we have

y=2x-1

so m=2 and b=-1

soo they are the same line which means they have infinite solutions and they are consistent( the system) and dependant( the equations)

Hope this is what you were looking for if not repost and I will try and help!

4 cubed is 64, 3 squared is 9, so 55.

1. For finite sets, and some sets with no pattern you can write down the elements.

{a1, a2, a3, a4, ....., an} or {a1, a2, a3, ....} for infinite sets

e.g. {1, 3, 5, pi/sqrt(2)}

{1, 2, pi, 56, 4, i, sqrt(pi), ...}

You can do this with all sets, there is no order required.

2. If there is a generic way of describing the set, as in there is one universal pattern for all of them then you can write:

{x | x satisfies P(x)} where P is a condition

2'. For sets have a name and a symbol, for instance the natural numbers, just write the symbol.

bolded N for natural numbers

3. If a set is countable, meaning its elements can be written in a sequence an (a sequence is an infinite order of "numbers" with respect to the natural numbers) then you can write:

{an} to represent the set.

e.g. (an) = ((-1)^n) = (-1, 1, -1, 1, -1, 1, -1, ...).

Then we can say {an} = {(-1)^n} but there are only two distinct elements, so it's also {1, -1}

A better one. (bn) = (1/2^n) = (1/2, 1/4, 1/8, 1/16, ....)

Write {1/2^n} suffices.

Note: You have to specify that n is a natural number beforehand so both the sequence and set notation makes sense

Can't think of a fourth way yet.

It has to equal 3 because if you plug it in to the equation you get:

(1+3)/2 = 2

4/2 = 2

2=2 check.

To SOLVE for the equation you have to set the whole thing equal to X.

(1+X)/2 = 2

1. Multiply both sides by 2. (2)(1+X)/2 = 2 (2)

2. subtract 1 from both sides. 1+X = 4 X-1 = 4 -1

3. This will give you your answer of 3. X = 3

The standard form is 7x + 2y - 3 = 0

X - 6 = 1

add 6 to each side

X = 7

====

So, - 5 is not a solution here.

(1/x) + (1/y) + (1/z) is a minimum value when x=y=z=10.

Symmetry gives either maximum or minimum value.

t = 2*pi*sqrt(L/g) where L is the length of the pendulum and g is the force of gravity.