We can rewrite this as 2x2 -6x-1=0
Now if you want to solve this, you can use the quadratic equation.
a=2
b=-6
c=-1
So x= [6+ or - ( square root of (36+8) ]/ 4
= [6+ or - (2square root of (11))/]4
Find all the solutions to the equation 2u4 plus 38u2 equals 16u3 plus 24u?
2u4 + 38u2 = 16u3 + 24u
∴ u3 - 8u2 + 19u - 12 = 0
∴ (u - 3)(u2 - 5u + 4) = 0
∴ (u - 3)(u - 4)(u - 1) = 0
∴ u ∈ {1, 3, 4}
* * *
Because u is a factor of both sides of the equation given,
u = 0 is also a solution.
What is x equals y squared minus 2?
Im assuming you are trying to come up with a y intercept equation for a graph. If that assumption is correct
x = y^2 - 2
y^2 = x + 2
y = SQRT ( x + 2 )
What is the volume of a rectangular prism that has the dimensions 14 in x 8 in x 6 in?
14*8*6 = 672 cubic inches.
How do you solve -3x-8 plus 4x equals 17?
-3x-8+4x=17
(-3x+4x)-8=17 ;combine like terms
(x)-8=17 ;add 8 to both sides
x=25
Do your own homework.
This is fairly simple but if you can't work it out youself try substituting in whole number values for X, one at a time, and keep going until you find the number that works.
Ps This is not Calculus! If you can't do this I would avoid calclus like the plague!!
What is the answer to 12x-41 equals 6x plus 1?
12x-41=6x+1
add 41 to both sides
12x=6x+42
subtract 6x from both sides
6x=42
divide both sides by 8
x=7
What is the value of x in 3x-6 plus 1 equals 7?
3x - 6 + 1 = 7
Combine the -6 and the +1 on the left side of the equation :
3x - 5 = 7
Add 5 to each side:
3x = 12
Divide each side by 3 :
x = 4
How do you solve x squared minus 15 equals 2x?
How do you graph the function y equals x over 10?
Well, the best way I think is to form a table with X and Y values. For example:
When X = 0 Y = 0 because Y = 0/10 (plug 0 for X)
When X = 5 Y = 5/10 or 1/2 etc...
Do this for both positive and negative number and plot your X and Y values...it's a linear equation so it'll be a line that goes through (0,0). Using the above examples, you should have a plot point at (0,0) and (5, .5)
Is 3x plus 27 equals 8 a quadratic function?
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
What is the solution of the system 2x-y55 and x plus 2y2?
2x - y = 55
x + 2y = 2
Multiplying the second equation by -2 gives us
2x - y = 55
-2x - 4y = -4
Adding both equations together gives us
-5y = 51
y = -10.2
Plugging that back into one of the original equations gives
x + 2(-10.2) = 2
x - 20.4 = 2
x = 22.4
So x = 22.4 and y = -10.2
d2P/dV2 = 2RT(V - b)-3 + a[(2*sqrt(T))*(V2sqrt(T) + Vb*sqrt(T))-2 - 2(V2*sqrt(T) + V*sqrt(T))-3*(2V*sqrt(T) + b*sqrt(T))2]
Assuming your question is interpreted as follows:
y=abcx
This function is an exponential function. Since a, b, and c are constants, it is simply a constant number raised to a variable power. A simple version of this would be:
y=2x
For this example, a or b can equal 2 while the other equals 1, and c=1.
x2 - 2x - 5 = 0
By the quadratic equation,
x = {2 +/- sqrt[(-2)2 - 4*1*(-5)]}/2
= {2 +/- sqrt(4+20)}/2
=1 +/- sqrt(6)
What is the solution to 2x plus 1 equals 7-10x?
The solution is 1/2 or 0.5.
This is how:
2x+1=7-10x
2x=6-10x
12x=6
x=1/2