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Computer Networking
Computer networks are collections of computers which are connected together in order to communicate and transfer information. Questions about computer networks, networking protocols, and how to set them up belong here.
18,810 Questions
Application layer protocols: DNS and HTTP
Transport layer protocols: UDP for DNS and TCP for HTTP
IP address is a special order of digits which uniquelly identifying computer in network. URL is understandable name for people which corresponds to certain IP address. It's not easy for most people to remember IP address but much easier to remembers URLs which have usually really simple name which not hard to remember. You can call website either by URL or by IP address.
What factors contribute to the success of Ethernet?
The Ethernet has been successful because it has technology which is compatible with many devices. The networking technology needed is also affordable to most households and businesses.
Coverage of wireless access point?
Fifty feet to five hundred feet. It depends on the type of access point and the physical area where it is installed.
What is a network interface card?
Very simply, a network interface card is a computer component that will slot into a socket on a PC motherboard with the back of the card providing one or more Ethernet connection sockets. The card is required to connect a PC to the internet via a wired connection. The card has a hard wired MAC address identifies the device uniquely on the network.
Modern PCs can also connect to the Internet wirelessly via a PC bus card or a USB device connection - these devices could also be called network interface cards.
What arae the advantages of intercom?
Intercoms help you remain safe when included in a security system. For businesses intercoms help management increase productivity by eliminating walking.
What are three characteristics of valid Ethernet Layer 2 addresses?
- They are 48 binary bits in length.
- They are generally represented in hexadecimal format
- They are considered physical addresses
Secure Digital Input/Output, Wireless Local Area Network card. SDIO is the new,secure, interoperability standard
31,6 watts
in EBCDIC: 11001000, 10000101, 10010011, 10010011 10010110
in ASCII: 1001000, 1100101, 1101100, 1101100, 1101111
in Unicode: 0000 0000 0100 1000, 0000 0000 0110 0101, 0000 0000 0110 1100, 0000 0000 0110 1100, 0000 0000 0110 1111
What is the decibel loss of a signal that starts at point A with a strength of 2000 watts and ends at point B with a strength of 400 watts?
That is impossiple. If you have a light bulb of 100 watts. This power stays fixed in the lamp and does not decrease with distance!
If you mean a sound source, only the sound pressure in pascals or the sound pressure level in dB is decreasing with distance from the source. Or the sound intensity in watts per square meter or the sound intensity level in watts is decreasing with distance.
Scroll down to related links and look at "Sound intensity I and the inverse square law 1/r2"
This question is talking about the fundamentals between data and signals in data communication. It has nothing to do with a light bulb and is not impossible. Here is how it is done. The decibel is a relative measure of signal loss or gain and is expressed as dB = 10 × log10 (P2 / P1) in which P2 and P1 are the ending and beginning power levels of the signal expressed in watts.
So in this case where a signal starts with a strength of 2000 watts and ends with a strength of 400 watts the calculation would be:
dB = 10 × log10 (400 /2000)
dB = 10 × log10 (.2)
dB = 10 × (-.69)
dB = -6.9dB
What is the decibel loss of a signal that loses half its power during the course of transmission?
When the power (energy) is dropped to the value of 50 percent, the decibel loss is 3 dB, but the voltage is dropped to the value of 70.1 percent. Power drop to 50 % means -3 dB; that is 70.1 % voltage drop. Power drop to 25 % means -6 dB; that is 50 % voltage drop.
Nyquist has shown that
C=2 B log2 (M) [bps]
C: Capacity
B: Bandwidth
M: Signaling Levels
log2 (x)= [ log10 (x) / log10 (2) ]
So
We assume
F1=0Hz
F2=20kHz
so
B= F2-F1=20000 Hz
C = 2*20000* log2 (16) = 2*20000* log10 (16) / log10 (2) = 160 000 bps
Integration between DHCP and DNS?
Traditionally, DNS and DHCP servers have been configured and managed one at a time. Similarly, changing authorization rights for a particular user on a group of devices has meant visiting each one and making configuration changes. DHCP integration with DNS allows the aggregation of these tasks across devices, enabling a company's network services to scale in step with the growth of network users, devices, and policies, while reducing administrative operations and costs.
This integration provides practical operational efficiencies that lower total cost of ownership. Creating a DHCP network automatically creates an associated DNS zone, for example, reducing the number of tasks required of network administrators. And integration of DNS and DHCP in the same database instance provides unmatched consistency between service and management views of IP address-centric network services data.
Windows Server 2003 DNS supports DHCP by means of the dynamic update of DNS zones. By integrating DHCP and DNS in a DNS deployment, you can provide your network resources with dynamic addressing information stored in DNS. To enable this integration, you can use the Windows Server 2003 DHCP service.
The dynamic update standard, specified in RFC 2136: Dynamic Updates in the Domain Name System (DNS UPDATE), automatically updates DNS records. Both Windows Server 2003 and Windows 2000 support dynamic update, and both clients and DHCP servers can send dynamic updates when their IP addresses change.
Dynamic update enables a DHCP server to register address (A) and pointer (PTR) resource records on behalf of a DHCP client by using DHCP Client FQDN option 81. Option 81 enables the DHCP client to provide its FQDN to the DHCP server. The DHCP client also provides instructions to the DHCP server describing how to process DNS dynamic updates on behalf of the DHCP client.
The DHCP server can dynamically update DNS A and PTR records on behalf of DHCP clients that are not capable of sending option 81 to the DHCP server. You can also configure the DHCP server to discard client A and PTR records when the DHCP client lease is deleted. This reduces the time needed to manage these records manually and provides support for DHCP clients that cannot perform dynamic updates. In addition, dynamic update simplifies the setup of Active Directory by enabling domain controllers to dynamically register SRV resource records.
If the DHCP server is configured to perform DNS dynamic updates, it performs one of the following actions:
- The DHCP server updates resource records at the request of the client. The client requests the DHCP server to update the DNS PTR record on behalf of the client, and the client registers A.
- The DHCP server updates DNS A and PTR records regardless of whether the client requests this action or not.
By itself, dynamic update is not secure because any client can modify DNS records. To secure dynamic updates, you can use the secure dynamic update feature provided in Windows Server 2003. To delete outdated records, you can use the DNS server aging and scavenging feature.
Edge server's task is mainly to give users (clients) content on webpages and other related contents. Normally the edge server's are connected to the ISP (Internet Service Provider).
How can you make a blank without name folder?
To rename the folder with blank spaces, just press Alt + 255 and hit Enter
802.11a channels are full duplex or half duplex?
802.11 anything is half duplex in practice. Only one station can speak at a time because of the CSMA/CA algorithm. It's the only way to ensure that there is no "collision" between 2 transmitting stations on a single channel. Mind you, that the CSMA/CA algorithm is applied per channel, not per SSID. So, if you have a neighbor on the same channel as you, both of your APs and all stations on the same channel are competing for "talk time" on the channel.
40 meters equals how many feet?
forty meters equals about 131 feet
Direct Conversion Formula 40 m*
1 ft
0.3048 m
=
131.2335958 ft
Examples of cell specialization?
Cell specialization is the process in which a generic cell develops into a specific type of cell. This happens in response to specific triggers from the body or the cell itself. Three examples of specialized cells are the sperm cell, the fat cell, and the white blood cell.
You want to communicate with your other personal computer?
The best way to communicate with your other personal computer when away is through remote sharing. Most computers have the ability to enable remote sharing with password set-up to allow communication from other devices and locations.
The bus cable to which computers on the Ethernet is connected?
The bus cable to which computers on the Ethernet is connected is called the trunk. If the trunk breaks, a bus topology is completely disrupted.
A networking hub is a device that relays data communication. It sends data packets to all devices that are within a network, regardless of any MAC addresses it contained.
Calculate hamming code between 1000110 and 1110100?
hamming code between 1000110 and 1110100 can be calculated by just exoring both codes with each other as follow: 1000110 1110100 ------------ 0110010 now by counting the ones in the result that gives 3 then hamming dictance = 3
If you have a hub alreadly and want wireless internet how do you go upon doing this?
You need to buy a wireless router and connect it to the modem.
