What are the key differences between academic and casual communication styles?
The difference between academic and casual communication. Casual communication is more of socializing with family and friends and co-workers and academic is speaking in a more professional manner. Adhering more to the words and the proper language use. You would not normally speak in a professional manner on a daily basis unless you are in a professional surrounding 24/7.
What is the role of pnp and military?
PNP Positive Negative Positive, is a type of Transistor. I don"t know of military applications.
On a silicon-controlled rectifier which wire is the anode and which the cathode?
Anode is positive, cathode is negative
A: first you must define the frequency of transmission. wave lenght is time from that you can calculate them total time
What causes the gain of OP AMP to roll off after a certain frequency is reached?
A: Any amplifier will reach a frequency cut off point because of hindered circuit capability however the roll of bust be controlled especially when reaching oDB point must be at a -3 db roll off to prevent hi frequency oscillation
What is the behavior of an inductor?
An inductor resists a change in current. The equation is ...
di/dt = V/L
... where di/dt is the rate of change of current in amperes per second, V is the EMF is volts, and L is the inductance in henrys.
Looking at this, you can see that the slope of the current is proportional to the voltage and inversely proportional to the inductance.
One characteristic of inductors is that when you have a current established, and then break the circuit, the inductor will respond by trying to maintain the current. If this is not possible, such as when the circuit is open, the inductor will generate a large reverse EMF - in the theoretical case, an infinite EMF - in the practical case, several thousand volts, depending on the inductor. This is why proper design of inductors in DC circuits, such as relays and solenoids, must include reverse EMF suppression, such as a diode or resistor across the inductor.
Transformer Output power less than input power?
A: Absolutely a power transfer will have an internal loss of IR . for a power transformer the loss can be as much of 20% or more if other magnetics are involved like iron screw holding the lamination together. Usually brass is used to reduce that loss.
Why ce configuration of transistor has a 180 phrase difference in output?
A: As current begins to flow the action on a resistance will be a voltage drop which is inversely proportional to the current. Making it a voltage amplifier as opposed to a tube where it is a current amplifier
diode:= di+ iode
di means two,and iode means terminal,,,, diode is two terminal device i.e anode and cathode
What is the function of askerals in a transformer?
its a type of transformer oil which provides insulation ...
Electrical power is expressed in watts or?
Electrical power is expressed in watts or in jouls per second
Another Answer
There is no such thing as 'electrical power'. Power is simply a rate: the rate of doing work. Power can be measured in watts (in the SI system) or in horsepower (in the Imperial system). There is no reason why the power of a heater can't be measured in horsepower or the power of a car can't be measured in watts.
Why intermediate frequency transformers are used in modulation process?
They are used as adjustable bandpass filters in superheterodyne (Google it) recievers. They determine how well you can select the radio station you require, while rejecting those close to it. They work in a fixed frequency range where their characteristics can be optimised.Very many modern radio recievers use some form of the superheterodyne principle though the function of the IF Transformer (ie bandpass filter) can be realised digitally, as in mobile phones for example. For AM radio a bandwidth of 9 KHz at 450KHz is typical.
The NPN transistor when used as an amplifier is operating in linear mode, and, when operating as a switch, in saturated mode.
In the following discussion, base currrent means base-emitter current, while the base is more positive than the emitter, and collector current means collector-emitter current, while the collector is more positive than the emitter. There is base-collector current, but we are going to ignore it for now - besides, we are going to discuss class A, common emitter, configuration.
The PNP transistor is very similar. Everything is backwards, including Vcc, which is now -Vcc, or appropriate reconfiguration. The rules are the same - just backward.
In switched or saturated mode, the ratio of base to collector current is far greater than beta-dc, or hFe, so the transistor is operating way out of its linear mode. We call that saturated mode, and the transistor is essentially either fully on or fully off, and therefore operating as an on-off switch.
The rest of this discussion will focus on linear or amplilfier mode.
If the ratio of base to collector current is less than beta-dc, or hFe and, if both base and collector voltage are greater than cutoff voltage, then the transistor is operating in linear mode. Well, sort of, for best linear mode, we look at the data sheet, or make empirical observations, and we pick the base and collector currents that are centered between the base knee and the collector knee, i.e. "in the middle of" the linear region.
In this mode, a very small base current can control a much larger collector current, and, most importantly, a very small change in base current can create a much larger change in collector current.
In the theoretical case, for example, where the emitter is grounded and where hFe is 100, then 1 mA of base current translates to 100 mA of collector current, and 2 mA of base current translates to 200 mA of collector current. Problem is, that hFe varies amongst even so called identical transistors, and hFe varies as a function of temperature as well.
So, in the practical case, an emitter resistor is added to stabilize the transistor and place limits on the need for hFe of a particular value. Done properly, this will yield predictable gain for various transistors and for various temperatures.
Now, lets look at how gain works in the practical sense. The base voltage is also a known delta above emitter voltage. Yes, temperature will affect this, but proper design can make this a negligable factor. The emitter current times the emitter voltage results in a known voltage. By Norton's current law, the base current and the collector current add up to be the emitter current, but by hFe, the base current is very much smaller than collector current, meaning that the really important part is that collector and emitter current are the same for all practical purposes.
So, now add a collector resistor. Ignoring base current, the collector/emitter circuit is a series circuit, and Norton's current law, reinterpreted for series circuits, says the two resistors have the same current. Think about what that means; if the current in both resistors is the same, then the ratio of the voltage across the two resistors is proportional to their value. The gain of the amplifier is collector resistor divided by emitter resistor. That is critical knowledge. Again, base current enters into the equation but, if hFe is high enough, it does not matter.
All that is left, then, is to bias the base. You want to pick a base voltage (current) that places the collector current in the center (or in an appropriate point) of the linear region. Choose a nominal hFe, divide by collector current, and you get an approximation of what base current bias should be. Choose a resistor divider to match, keeping in mind that the two resistors (base to Vcc and base to Gnd) in parallel will reflect your effective input impedance.
Review everything, particularly your power levels. To calculate the power through the collector/emitter junction subtract collector resistor voltage from emitter resistor voltage from Vcc, and you get collector/emitter voltage. Multiply that by collector current, and you get power dissipated by the transistor in nomial bias condition.
Play with the values until you have what you want. You could even set this up in a spreadsheet.
Last, but not least, there is a base bias voltage. If you are going to amplify something, you need to maintain that nominal bias voltage. Connect a series capacitor between the base and the input point and you will be able to operate from an AC signal that is zero referenced. Just pick the RC time constant appropropriate for your application.
Similarly, there is a collector bias, so, if you want an AC output zero referenced, use a series capacitor also in between the collector and the ouput.
This is an AC coupled, inverting amplifier. There are DC coupled non-inverting versions, but they are more complicated, requiring more than one transistor, and this answer does not address them. Good luck!
3 dB is a change in power by a factor of 2. If it is plus, i.e. +3dB, power is doubled. If it is minus, i.e. -3dB, power is halved.
6 dB, then is a factor of four, or quarter; 6 dB is a factor of eight, or eighth, etc.
The actual equation is 3 log2 (POWER OUT / POWER IN).
What angle is the voltage increasing at its fastest rate?
This is a simple derivation problem. Take the derivative of the AC voltage waveform (I'll assume sin (t)), and set the derivative equal to the maximum value it can attain (which is 1):
cos (t) = 1, t = 0 degrees, thus for an AC waveform of y = sin(t), the fastest increase in voltage occurs at 0, 360, etc. degrees. The fastest decrease in voltage will occur at 180, 180 + 360, etc. degrees.
Negative feedback is most like?
Taking a step, feeling yourself imbalanced, and compensating by shifting your weight on the fly in order to maintain balance. You could simplify it further by saying that even just standing still requires a negative feedback loop in order to stay standing.
What is the re-model of npn common base transistor?
Thus if we go back to the
circuit model for the common emitter transistor, and
re-draw it as a small signal model it would look
something like Figure 1. Here we have replaced the
diode with a linear element (a resistor, called
rπ)
and we have changed the notation for the currents from
IB
and
IC
to
ib
and
ic
respectively, to remind us that we are now talking about small signal
ac quantities, not large signal ones. The bias currents
IB
and
IC
are still flowing through the device (and we will leave it to ELEC 342
to discuss how these are generated and set up) but they do not appear
in the small signal model. This model is only used to figure out how
the transistor behaves for the ac signal going through it, not have
it responds to large DC values.
Figure 1: Small signal linear model for the common emitter transistor
Figure 1 (3.16.png)
Now
rπ
the equivalent small signal resistance of the base-emitter diode
is given simply by the inverse of the conductance of the
equivalent diode. Remember, we found
rπ===1qkTIB1qkTICββ40IC
(1)
where we have used the fact that
IC=βIB
and
qkT=40V-1.
As we said earlier, typical values for βin a standard bipolar transistor will be around
100. Thus, for a typical collector bias current of
IC=1mA,
rπ
will be about 2.5 kΩ.
There is one more item we should consider in putting together our
model for the bipolar transistor. We did not get things completely
right when we drew the common emitter characteristic curves for the
transistor. There is a somewhat subtle effect going on when
VCE
is increased. Remember, we said that the current coming out of the
collector is not effected by how big the drop was in the reverse
biased base-collector junction. The collector current just depends
on how many electrons are injected into the base by the emitter,
and how many of them make it across the base to the base-collector
junction. As the base-collector reverse bias is increased (by
increasing
VCE
the depletion width of the base-collector junction increases as
well. This has the effect of making the base region somewhat
shorter. This means that a few more electrons are able to make it
across the base region without recombining and as a result
α and hence
β increase somewhat. This then
means that
IC
goes up slightly with increasing
VCE.
The effect is called base width modulation.
Let us now include that effect in the common emitter
characteristic curves. As you can see in Figure 3,
there is now a slope to the
IC(VCE)
curve, with
IC
increasing somewhat as
VCE
increases. The effect has been somewhat exaggerated in Figure 2, and I will now make the slope even bigger so
that we may define a new quantity, called the Early
Voltage.
Figure 2: Common emitter response with base-width modulation
effectFigure 2 (3.17b.png)
Figure 3: Finding the Early VoltageFigure 3 (3.18b.png)
Back in the very beginning of the transistor era, an engineer
at Bell Labs, Jim Early, predicted that there would be a slope to the
IC
curves, and that they would all project back to the same
intersection point on the horizontal axis. Having made that
prediction, Jim went down into the lab, made the measurement, and
confirmed his prediction, thus showing that the theory of
transistor behavior was being properly understood. The point of
intersection of the
VCE
axis is known as the Early Voltage. Since
the symbol
VE,
for the emitter voltage was already taken, they had to label the
Early Voltage
VA
instead. (Even though the intersection point in on the negative
half of the
VCE
axis,
VA
is universally quoted as a positive number.)
How can we model the sloping I-V curve? We can do almost the
same thing as we did with the solar cell. The horizontal part of
the curve is still a current source, and the sloped part is
simply a resistor in parallel with it. Here is a graphical
explanation in Figure 4.
Figure 4: Combining a current course and a resistor in parallelFigure 4 (3.19.png)
Usually, the slope is much less than we have shown here, and so
for any given value of
IC,
we can just take the slope of the line as
ICVA,
and hence the resistance, which is usually called
ro
is just
VAIc.
Thus, we add
ro
to the small signal model for the bipolar transistor. This is
shown in Figure 5. In a good quality modern
transistor, the Early Voltage,
VA
will be on the order of 150-250 Volts. So if we let
VA=200,
and we imagine that we have our transistor biased at 1 mA, then
ro==200V1mA200kΩ
(2)
which is usually much larger than most of the other resistors you
will encounter in a typical circuit. In most instances,
ro
can be ignored with no problem. If you get into high impedance
circuits however, as you might find in a instrumentation
amplifier, then
vbe
has to be taken into account.
Figure 5: Including ro in the small signal linear modelFigure 5 (3.20.png)
Sometimes it is advantageous to use a mutual transconductance
model instead of a current gain model for the transistor. If we
call the input small signal voltage
vbe,
then obviously
ib==vberπvbeβ40IC
(3)
But
ic=βib=βvbeβ40IC=40ICvbe≡gmvbe
(4)
Where
gm
is called the mutual transconductance of the transistor.
Notice that β
has completely cancelled out in the expression for
gm
and that
gm
depends only upon the bias current,
IC,
flowing through the collector and not on any of the physical
properties of the transistor itself!
Figure 6: Transconductance small signal linear modelFigure 6 (3.21.png)
Finally, there is one last physical consideration we should make
concerning the operation of the bipolar transistor. The
base-collector junction is reverse biased. We know that if we
apply too much reverse bias to a pn junction, it can breakdown
through avalanche multiplication. Breakdown in a transistor is
somewhat "softer" than for a simple diode, because once a small
amount of avalanche multiplication starts, extra holes are
generated within the base-collector junction. These holes fall up,
into the base, where they act as additional base current, which,
in turn, causes
IC
to increase. This is shown in Figure 7.
Figure 7: Ionization at the base-collector junction causes additional
base currentFigure 7 (3.22.png)
A set of characteristic curves for a transistor going into
breakdown is also shown in Figure 8.
Figure 8: Bipolar Transistor going into breakdownFigure 8 (3.23b.png)
Well, we have learned quite a bit about bipolar transistors in a
very short space. Go back over this chapter and see if you can
pick out the two or three most important ideas of equations which
would make up a set of "facts" that you could stick away in you
head someplace. Do this so you will always have them to refer to
when the subject of bipolars comes up (In say, a job interview or
something!).
What is relation between roll off factor bandwidth and bit rate?
The roll-off factor of a digital filter defines how much more bandwidth the filter occupies than that of an ideal "brick-wall" filter, whose bandwidth is the theoretical minimum Nyquist bandwidth.
The Nyquist bandwidth is simply the symbol rate expressed in Hz:
Nyquist Bandwidth (Hz) = Symbol Rate (Sym/s)
However, a real-world filter will require more bandwidth, and the excess over the Nyquist bandwidth is expressed by the roll-off factor. Suppose a filter has a Nyquist bandwidth of 100 MHz but actually occupies 120 MHz; in this case its roll-off factor is 0.2, i.e. the excess bandwidth is 0.2 times the Nyquist bandwidth and the total filter pass-bandwidth is 1.2 times the Nyquist bandwidth.
How do you increase amperage without changing voltage or resistance?
You cannot increase amperage without changing voltage or resistance.
Ohm's law states that voltage is current times resistance. You cannot change one alone.
Not even changing frequency in a capacitive or inductive circuit will do this, because changing frequency represents a change in reactance, which is effectively a change in resistance.
What is the function of a sensistor?
the sensistor functions as a temperature sensitive resistor with a positive coefficient of temperature.used for temperature compensation in various circuits
What is the resistance of a power cord?
It depends on the size of the cord and the volts it carries-
But to find how much VOLTAGE a wire consumes...
It could be found by V = I X R
Usually the resistance of electrical wires is not TOO important- its important when you try to force large amounts of current through a long piece of wire. So lets say a wire is very long and was connected to a battery that had 15 volts and the resistance of the thin wire is 0.2, V=15 x 0.2 = 3 volts. Three volts is not a big deal if you have a high voltage power supply, but if you are using say a 12 volt car battery the length of the wire would take one quarter of the available voltage-which is why a automotive batteries cable is thick -to reduce its resistance below 0.2Ohms.
This is still sort of an in-direct answer- but it might help.