Newtons Laws of Motion

Having no force acting at all, as the forces will cancel each other out. This results in a net force of zero.

If we take F1 to be in the direction of a unit vector "i" and the direction perpendicular to the direction of F1 to have a unit vector "j" , F (net) = ((15*cos(60))+20) i + (15*sin(60)) j

= 27.5 i + 12.99 j N

Mass * Acceleration = F (net)

=> Acceleration = F (net) / mass

Acceleration = (3.4375 i + 1.62375 j ) m/sec2

Newton's second law for rotational motion states that the net torque acting on an object is equal to the product of the object's moment of inertia and its angular acceleration, similar to how force is related to acceleration in linear motion. Mathematically, this can be written as τ = Iα, where τ represents torque, I is the moment of inertia, and α is the angular acceleration.

The Harrier Jump Jet, specifically the AV-8B Harrier II, is capable of vertical takeoff and landing (VTOL) due to its unique design with thrust vectoring nozzles that allow for vertical flight. This feature allows the aircraft to operate from shorter runways and in locations where traditional takeoff and landing may not be possible.

Sphere radius, R = (28 cm)/2 = 14 cm = 0.14 m

Speed, v = 2 m/s

Mass, M = 2.5 kg

Rotational KE = ½𝙸𝜔²

For solid sphere, the moment of inertia, 𝙸 = ⅖MR²

Rotational KE = ½(⅖MR²)(v/R)²

= ⅕Mv²

= ⅕(2.5 kg)(2 m/s)²

= 2 J

Total KE = Linear KE + Rot KE

Total KE = ½Mv² + ⅕Mv²

Total KE = (7/10)(Mv²)

Total KE = (7/10)(2.5 kg)(2 m/s)²

Total KE = 7 J

Angular momentum, 𝜔 = v/R = (2 m/s)/(0.14 m) = 14.3 rad/s

The normal force is what prevents an object from falling through the ground.

The force of gravity is equal to the product of the mass and acceleration due to gravity, so the ground that the object sits on must apply an equal force in the opposite direction (Newton's Third Law), other wise the object would fall through.

If a person pushes upward on a box with a force equal to or greater than the box's weight, the box will either stay at rest or accelerate upwards. This is because the force applied by the person cancels out the force of gravity acting on the box. If the force applied is greater than the weight of the box, the box will accelerate upwards due to the net force acting on it.

Well, that's a pretty broad question with many many many answers. Pretty much anytime you see something where nothing is happening, there are balanced forces at work. A book on a table, for example: The table is pushing up on the book with the same amount of force that the book is pushing down on the table. However, sometimes even when it appears that something IS happening, balanced forces can be found. For example, an airplane, in level flight (neither climbing nor decending) and is neither accelerating nor decelerating has 2 obvious pairs of balanced forces: Gravity and Lift are in balance, since the plane is neither ascending nor descending, and thrust and drag are in balance since it's neither accelerating nor decelerating.

Second law: The acceleration a of a body is parallel and directly proportional to the net force F and inversely proportional to themass m., F = ma.

We use the term inertia to describe the resistance of an object to any change in its motion. If an object is not moving, it doesn't want to move. If it is moving, it doesn't want to change is speed or the direction it is moving. This is covered by Newton in his laws of motion.

f = m g

This is the formula for the force on an object due to gravitational attraction
between it and a second object.

f = the force on the object
m = the object's mass
g = the acceleration of gravity due to the presence of the second object

When the second object is the earth, 'g' is 9.8 meters per second2,
and 'f' is what is called the first object's 'weight'.

Some common topics for a physics chart for class 11 could include motion, forces, energy, waves, and electricity. These topics cover a wide range of important concepts in physics that are often studied at the high school level.

The linear acceleration of the sphere down the incline can be calculated using the formula (a = g \sin(\theta)), where (g) is the acceleration due to gravity (9.8 m/s(^2)) and (\theta) is the angle of the incline. Substituting the values, we get (a = 9.8 \times \sin(30) = 4.9 , \text{m/s}^2).

The minimum coefficient of friction required to prevent slipping can be calculated using the formula (\mu_{\text{min}} = \tan(\theta)), where (\mu_{\text{min}}) is the minimum coefficient of static friction. Substituting the values, we get (\mu_{\text{min}} = \tan(30) \approx 0.577).

The MKS unit of force is the Newton (N). It is used to measure the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

Increasing the spring stiffness will result in a higher natural frequency. This is because a stiffer spring will require more force to displace it, leading to faster oscillations and a higher frequency. Conversely, decreasing the spring stiffness will lower the natural frequency of the system.

For each little 'bounce', the runner has to expend the energy to raise his weight by those few inches ... which gravity immediately reverses as it pulls him down to his original elevation. None of this adds anything to his forward progress. So in the course of the same forward distance, the bouncer expends more total energy than the guy who keeps his center of mass at a constant elevation.

The maximum height of the ball above the ground can be calculated using the vertical component of the initial velocity. Assuming no air resistance, the formula to determine maximum height is h = (v^2 sin^2(theta)) / (2g), where v is the initial velocity (16 m/s), theta is the angle (40 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, you can find that the maximum height of the ball is approximately 14.1 meters.

acceleration
The rate at which velocity changes is called "acceleration".

A block and tackle provides a mechanical advantage by trading distance for force. The user needs to exert less force to lift a heavier load, but they have to pull the rope a greater distance to accomplish the task.

Some specialized cells in our body like macrophages and leucocytes

in blood exhibit amoeboid movement. It is affected by pseudopodia formed

by the streaming of protoplasm (as in Amoeba). Cytoskeletal elements

like microfilaments are also involved in the amoeboid movement

watch?v=4s_wZzZhdaw

Yes, the resulting observed value of g would be different if the falling body had been given an initial downward push instead of being released. The initial downward push would have added an additional force to the falling body, affecting its acceleration and ultimately the observed gravitational acceleration.

Yes, the law states that an object continues its state of rest or uniform motin in a straight line unless it is compelled to change that state by an external source impressed upon it.

Number of independent coordinates that are required to describe the motion of a system is called degrees of freedom. In a system of N -particles, if there are k -equations of constraints, we have n  3N  k number of independent coordinates. n  degrees of freedom

To get a trailer up to a speed v in a time t, you would need to get it accelerating at a rate of v/t. From F=ma, the net force on the trailer to achieve this would have to be mv/t. First, you'll need to apply a force greater than the static frictional force to get the trailer moving - then to get the desired acceleration, you'd apply a force F = mv/t + Ff where Ff is the kinetic friction of the axel/tires. So, once you overcome the static friction the required force to achieve velocity v in time t would be: F = mv/t + frictional force

When you push on a solid object, the force is transmitted through the object as a wave of increased pressure that causes the atoms and molecules within the object to move. This movement propagates through the object at the speed of sound within that material, leading to a delayed response at the other end of the object rather than an instantaneous reaction.