Oxidation Numbers

P = +5 PO4^3- = -3

4(-2) + p = -3

P =5

The oxidation number for hydrogen (H) is +1. Since there are 5 hydrogen atoms in H5P3O10, the total oxidation number contributed by hydrogen is +5. The sum of the oxidation numbers for all the atoms in a neutral compound is zero, so the sum of the oxidation numbers in H5P3O10 must also be zero. Therefore, the oxidation number of phosphorus (P) in H5P3O10 is +5.

The oxidation number of Al in NaAlH4 is +3. This is because Na has an oxidation number of +1, H has an oxidation number of -1, and the overall compound has a neutral charge. Therefore, the oxidation number of Al can be calculated as +3.

In sodium oxide (Na2O), sodium typically has an oxidation number of +1 and oxygen has an oxidation number of -2. Sodium readily gives up its outer electron to achieve a full valence shell, while oxygen typically gains two electrons to achieve a full valence shell.

oxidation is charge and it would be positive two in a ionic bond (that is what is referring to in oxidation number)

No, the oxidation number of CaCl2 is not 3. In CaCl2, calcium (Ca) has an oxidation state of +2, and each chlorine atom (Cl) has an oxidation state of -1. This combination allows for the compound to have a neutral charge.

MoS2.

-2 for each S, +4 for Mo

The charge of an element is based on its oxidation number, which is the number of electrons that an atom loses, gains, or shares when it forms a chemical bond. Oxidation numbers can be positive, negative, or zero, depending on the element and the chemical compound it is part of.

The oxidation number of calcium in calcium fluoride (CaF2) is +2, because calcium typically forms ions with a charge of +2. The oxidation number of fluorine in CaF2 is -1, because fluorine usually has a charge of -1.

The oxidation number of hydrogen in InH3 is +1. In compounds, hydrogen usually has an oxidation number of +1, as it has a tendency to lose its single electron to form a positive charge.

The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.

Predominantly those in wide form periodic table column 16, especially oxygen and sulfur.

The oxidation number of carbon (C) in glucose is +4. This is because in glucose (C6H12O6), each carbon atom is bonded to one oxygen atom, and oxygen is more electronegative than carbon, resulting in a higher oxidation state for carbon.

Yes, hydrogen can have oxidation numbers of +1 and -1. In compounds with metals, hydrogen tends to have an oxidation number of +1, while in compounds with nonmetals, hydrogen tends to have an oxidation number of -1.

The oxidation number of Fe in FeCO3 is +2. This is because the overall charge of the carbonate ion (CO3^2-) is -2, so the iron (Fe) must have an oxidation state of +2 to balance the charge of the compound.

In MgBr2, magnesium (Mg) has an oxidation number of +2 as it typically loses two electrons to achieve a stable octet. Bromine (Br) has an oxidation number of -1 since it typically gains one electron to complete its valence shell.

There are s8 sulfur molecules. It shows 0 oxidation number.

Oxidation numbers of the elements in NH4I are

N: -3

H: +1 (4 times)

I: -1

Overall:

NH4+ : +1

and I- : -1

The oxidation number of P in PCl3 is +3. This is because chlorine typically has an oxidation number of -1, and there are three chlorine atoms in PCl3, giving a total charge of -3. To balance this charge, the oxidation number of P must be +3.

The oxidation number of potassium is +1. Potassium is an alkali metal with one valence electron, which it tends to lose when forming chemical bonds.

The oxidation number for Ti in TiO2 is +4. This is because oxygen usually has an oxidation state of -2 and there are 2 oxygen atoms in TiO2, making the combined oxidation state from the oxygen atoms -4. Therefore, the titanium atom must have an oxidation state of +4 to balance the overall charge of the compound.

In HIO2, the oxidation number of hydrogen is +1 and oxygen is -2. To calculate the oxidation number of Iodine (I), you would set up the equation: (oxidation number of I) + 2(-2) + 1 = 0 (overall charge of the compound). By solving this equation, you can determine that the oxidation number of I in HIO2 is +3.

An oxidation number of 2 means the element has lost or gained 2 electrons in a chemical compound. The oxidation number is a measure of the element's ability to combine with other elements.

It shows some oxidation numbers. Generally it shows +4 oxidation numbers.

The oxidation number of iron in ferrousofericoxide (Fe3O4) is a combination of Fe(II) and Fe(III) ions. The Fe(II) ions have an oxidation number of +2, while the Fe(III) ions have an oxidation number of +3. Each formula unit of Fe3O4 contains two Fe(III) ions and one Fe(II) ion, resulting in an average oxidation number of +2.67 for iron in this compound.