Oxidation Numbers

The oxidation number of H in H2O is +1, and that of O is -2. Since there are three H2O molecules, the total oxidation number would be 3(+1) + 3(-2) = -3.

the charge on that ion

The oxidation number of H in HNO2 is +1, the oxidation number of N is +3, and the oxidation number of O is -2.

Cobalt has an oxidation number of 3 (III) in the compound Co2O3.

The oxidation number for Cl in ClO3 is +5. This is because oxygen has an oxidation number of -2 and there are 3 oxygen atoms in ClO3, resulting in a total oxidation number of -6. The overall charge of the ion is -1, so the oxidation number of Cl must be +5 to balance the charges.

Manganese oxidation state = +7

So, it is also called Manganate(VII)

The oxidation number of aluminum in aluminum chloride (AlCl3) is +3. Aluminum typically has an oxidation number of +3 when it forms ionic compounds.

0- any element by itself has an oxidation number of 0.

The oxidation number of sulfur in H2SO4 is +6. This is determined by assigning an oxidation number of +1 to hydrogen and -2 to oxygen. Since the overall charge of the molecule is 0, sulfur must have an oxidation number of +6 to balance the charges.

the most common oxidation number for oxygen is -2.

oxidation is the process that occurs when a substance combines with oxygen, or any chemical process where there is a loss of electrons charge is also known as the oxidation number (oxidation state). which is a number assigned to an element, to represent how many electrons it has. for example hydrogen has a charge of +1 oxygen has a charge of -2

2 apex

The oxidation number of an uncombined element is zero. Uncombined elements, also known as elemental forms, have no charge and are considered to have an oxidation number of zero in their pure state.

Think about it, the overall charge of CaH2 is neutral (meaning a charge of 0). One of the oxidation rules states that H has a charge of -1 if it is apart of a hydride (Ex LiH, CaH2 is also a hydride). Because there are 2 Hs, it's charge would be -2. If you add the charge of calcium which is 2 with the hydrogens charge -2 you would get 0, which is right because the molecule is neutral.

1- Apex

Do you mean Aluminum Trisulfate Hectoxide? I dont know if it even exists but if it did, it would be
AlS3O20 or AlO20S3

The oxidation number of carbon in ethane (C2H6) is -3. This is because hydrogen is assigned an oxidation number of +1, and since the molecule is neutral, the sum of the oxidation numbers must be zero.

The oxidation number of lead (Pb) in lead nitrate (Pb(NO3)2) is +2. In this compound, the nitrate ion (NO3-) carries a charge of -1, and there are two nitrate ions for every lead ion. The overall compound must be electrically neutral, making the oxidation number of lead in lead nitrate +2.

The oxidation number of calcium is +2. Calcium typically loses two electrons to achieve a stable electron configuration.

It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.

In the compound Al2O3 oxygen is oxidized to minus 2. You will note that two aluminum times plus 3 is 6, and 3 oxygen times minus 2 is minus 6; thus the combination of aluminum and oxygen yields an electrically neutral molecule, since 6 - 6 = 0.

The oxidation number of NO3- is -1. Each oxygen atom typically has an oxidation number of -2, totaling -6 for the three oxygen atoms. Since the overall charge of the nitrate ion is -1, the nitrogen atom must have an oxidation number of +5 to balance the charge.

The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.

As SO42- has an overall -2 charge, The Oxygen has a -2 oxidation state, so to balance and give an overall -2 charge, the Sulfur has to have a +6 oxidation state.

(-2 x 4) + (s) = -2

s = +6

The oxidation number of Mn in MnO2 is +4. This is determined by assigning oxygen an oxidation number of -2, and knowing that the overall charge of the compound is zero.

the answer is 2, my chemistry proffessor told me so. take it or leave it.