Oxidation Numbers

The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.

The oxidation number for H is almost always 1+.

Out of these possible answers A) Ba(NO3)2(aq) + K2SO4(aq) -> BaSO4(s) + 2KNO3(aq)

B) HCl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l)

C) MgO(s) + H2)(l) -> Mg(OH)2(s) D) 2SO2(g) + O2(g) -> 2 SO3(g) E) 2H2O(l) -> 2H2(g) + O2(g)

Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium all have an oxidation state of plus 2.

The oxidation number of lead (Pb) in the compound PbCl2 is +2. This is because the oxidation number of chloride (Cl) is -1, and the overall charge of PbCl2 is 0, so the oxidation number of lead must be +2 to balance the charges.

The overall oxidation number for the phosphate ion (PO4) is -3. In the ion, each oxygen atom has an oxidation number of -2, so the phosphorus atom must have an oxidation number of +5 to balance the charges and give the ion an overall charge of -3.

Transition elements usually have more than one oxidation number. In different oxidation numbers, the ions show different colors. Some of the ranges: Cu from +1 to +2; Cr from +2 to +6; Ni from +2 to +3; Co from +2 to +3 and Mn from +2 to +7.

In the compound Co2O3 cobalt has an oxidation number of 3 while oxygen has an oxidation number is -2.

The oxidation number of oxygen in K2O2 is -1. Each oxygen atom in peroxide (O2^2-) has an oxidation number of -1.

Fluorine.

Oxygen has a -2 oxidation number in all compounds except peroxides and compunds with fluorine (+1 or +2)

Mg has +2, S has +6, O has -2

Explanation: O (oxygen) generally has -2 oxidation state ( exceptions exist like peroxides)

Mg(magnesium) is an alkaline earth metal which has fixed oxidation state of +2 in its compunds.

S(sulphur) shows variable oxidation state..

To get its oxidation state: we use the fact the total sum of oxidation state of all atoms in a compound is zero. For ions this sum is equal to the charge on the ion.

Let oxidation state of S be x.

Then we have: +2 (for Mg) + (-2)*4(for 4 O atoms) + x = 0

Which gives x=+6.

The oxidation number of Neon is 0. It does not want to gain or lose any electrons. It already has a full octet, therefore it remains at 0.

In Ag2SO4, the oxidation number of silver (Ag) is +1, sulfur (S) is +6, and oxygen (O) is -2. This is because the overall compound has a neutral charge, so the sum of the oxidation numbers must equal zero.

The oxidation number of sulfur (S) in Co2S3 is -2. This is because oxygen (O) usually has an oxidation number of -2 and cobalt (Co) has an oxidation number of +2, so the overall charge of the compound must be neutral, making sulfur's oxidation number -2.

0 in the elemental form

+2 in its compounds

The oxidation number of Calcium (Ca) is +2

0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....

The oxidation number of N, or Nitrogen, is N-3. Nitrogen is in group five, meaning it has five valence electrons. It needs to get eight to be stable. So it will gain 3 electrons to be stable. If you gain electrons, that makes it a negative number since electrons are negative in charge.

The oxidation number of Fe in Fe3+ is +3. This is because Fe is a transition metal and can exhibit multiple oxidation states. In this case, Fe has lost three electrons to form a 3+ charge.

The oxidation number of platinum is typically +2 or +4. Platinum is known to form compounds where it exhibits these oxidation states.

The oxidation number of phosphorus (P) in PBr3 is +3. This is because bromine (Br) has an oxidation number of -1 and since there are 3 bromine atoms in PBr3, the overall charge must balance out to zero.

+3 for Al and -2 for O is the oxidation number for Al2O3.

Thallium has an oxidation number of +1. Therefore, the formula for thallium carbonate would be Tl2CO3.

The oxidation number of IO3 is +5. Each oxygen atom in the IO3 ion has an oxidation number of -2, totaling -6 for all three oxygen atoms. Since the overall charge of the ion is -1, the iodine atom must have an oxidation number of +5 to balance the charges.