Probability

1/6 or 0.1667.

To calculate the odds of winning lotto where choose say 6 numbers out of 40 for example the calculation is 40X39X38X37X36X35 divided by 6X5X4X3X2X1 or about 3.8 million to 1 on any one line. If you have 45 numbers to choose from it would be 45X44X43X42X41X40/6X......etc or about 8.2 million to 1.

To the extent that I can make any sense of the question: Yes, the probability function for an s orbital is spherically symmetric and dependent on radial distance only.

It is 0.0039 approx.

hydro-pneumatic ambidextrously

2 out of 6

Without any other information, I would have to say: 69%.

Probability

It is 0.8217

0.94 inches is 11.28 twelfths of an inch.

0.94 x 12 = 11.28

p = 0

0 < p < 1

p = 1

52 cards, 4 of them 3s... 4 in 52 = 1 in 13 = ~7.7%

3.6

The probability is

2

-

6

one in six

1:6

six sides, one of which is a six

same odds for any of the numbers

There are four queens in a deck, one for each of the suits, spades, hearts, diamonds, and clubs.

The random variable has a Poisson distribution with parameter L = 1*50/20 = 2.5.

So Prob(at least one event in 50 years) = 1 - Prob(No events)

= 1 - L0e-L/0! = 1 - e-2.5 = 0.918 approx.

there should only be 4 queens in a deck of cards so 0.0%

1 billion seconds

16666666.67 minutes

277777.7778 hours

11574.07407 days

only about 75% because very often it is not equal

The probability of 3 heads and 3 tails is 0.3125

1 in 6. Wow.

The probability of drawing a seven in a standard deck of 52 cards is 4 in 52, or 1 in 13, or about 0.07692.

a.b..

a..b.

a...b

.a.b.

.a..b

..a.b

6 possible ways for two people not to sit next to each other

double that to 12 if b comes before a.

there is 1x2x3 = 6 possible for the dots on each of the above 12 combinations

so answer = 6x12 = 72

* * * * *

The correct answer is derived as follows:

The total number of ways of seating 5 people in a row is 5x4x3x2x1 = 120.

Rather than work out the number of ways in which the two people do not sit together, it is simpler to work out the number of ways in which they do sit together and subtract this from the total.

For this purpose, it is possible to treat the two people as one entity and so that gives 4*3*2*1 = 24 ways. However, this number needs to be doubled to allow for the two people to swap places: making 48 such ways.

The final answer, therefore, is 120 - 48 = 72 ways.

The probability of drawing an ace and then a seven from a standard deck of 52 card is (4 in 52) times (4 in 51), or 16 in 2652, or 4 in 663, or about 0.006033.

look at the weather