Probability

yes, since according to the 68-95-99.7 rule, the area within 3 standard deviations is 99.7%

4 kings in 52 cards

then 3 kings in 51 cards

4/52 * 3/51 = .00452488

It is one of the good sites .

... trust me it's 23/36 I got it wrong.

Without replacement:

P(one green and one blue) = P(drawing green then blue) + P(drawing blue then green)

= (6/23)(9/22) + (9/23)(6/22) = 104/506 = 52/253

With replacement:

P(one green and one blue) = P(green)*P(blue) = (6/23)(9/23) = 54/529

In 6!, or 720 ways.

The probability is the likely outcome of a random event. In this example - picking (say) the Ace of Spades - the chances are 1 in 52. Drawing a red card is 1 in 2, drawing a Spade is 1 in 13 etc.

The probability of drawing every card in order from a pre-written list is approximately 1 in 8 x 1067 !

Well, I guess the only way to "verify" such a probability would be to repeat the corresponding experiment millions of times.If you repeat a coin flip, or a die toss, sufficiently often, the combined probabilities increase exponentially. For instance, if you flip a coin, the probability to get heads is 1/2; if you flip the coin 20 times, and specify that you want heads EACH AND EVERY TIME, then the combined probability is, of course, 1/2 to the power 20 - or a bit less than one-millionth.

Similarly, you can toss a die sufficiently often - to figure out how often, just solve the inequality:

1/6 to the power x < 0.000001

Since you want a whole number, you can just try out a few numbers.

The answer depends on what you mean by "do". Does it mean calculate individually, calculate the probability of either one or the other (or both), calculate the probability of both, calculate some function of both (for example the sum of two dice being rolled)?

6-52

I believe the chances of having the same birthday as one of your parents is:

1 out of 183

and the chances of having the same birthday as both parents is:

1 out of 133,225

On a single roll, it is 1/6

sample size refers to the collection of data by only a selected size of te population through the process of sample surveys and sampling methods used in collecting data.

To get a three or less, you would need to roll a one on one die, and either a one or two on the second die. Since each face has a 1 in 6 probability, this gives:

P(3 or less on two dice) = ( P(1 on first die) * P(1 or 2 on second die) ) + ( P(2 on first die) * P(1 on second die) ) = (1/6 * 2/6) + (1/6 * 1/6) = 3/36, or 1/12.

P(3 or less on two dice) = 1/12

And yes, the singular of "dice" is "die". Stop changing it. Thanks.

3 over 6

P(7)= 1/30

1/6 chance.

Or a 16% chance

well, since on a die only 1 is less than two, the probability is 1/6, or .16666...

It is called empirical or experimental probability.

There is no simple answer since the times of conception may not be independent events.

Do more tests and go to a urologist. Could be urinary tract infection prompted by something your taking or doing. It could be as simple as wiping too hard. Take it easy and move to a softer tissue. But get a second opinion.

1/2 of a chance since there are two sides to any coins it is always a half chance.

There are four Aces in a standard deck of 52 cards. The probability, then, of not drawing an Ace is (52 - 4) in 52, or 48 in 52, or 12 in 13, or about 0.9231.

Digit 1 = 10 choices (0,1,2,3,4,5,6,7,8,9)

Digit 2 = 10 choices (0,1,2,3,4,5,6,7,8,9)

Digit 3 = 10 choices (0,1,2,3,4,5,6,7,8,9)

Digit 4 = 10 choices (0,1,2,3,4,5,6,7,8,9)

Number of combinations = 10 x 10 x 10 x 10 = 104 =10000

MTBF (mean time between failure)