Probability

There are 4 Queens in a pack of 52 playing cards.

My best thing Is to use a dime , that's the best luck you can get ... TRUST me , there Is NO Doubt (: & Throw the dime up in the air 4 times

------------------------------------------------------------------------------------------------

From Rafaelrz.

The probability of getting one head and 3 tails on a 4 coin toss is;

4C3 x (1/2)4 = 4!/[3!(4-3)!] x [1/2]4 = 0.25 or 25%

There may or may not be a benefit: it depends on the underlying distributions. Using the standard normal distribution, whatever the circumstances is naive and irresponsible. Also, it depends on what parameter you are testing for.

For comparing whether or not two distributions are the same, tests such as the Kolmogorov-Smirnov test or the Chi-Square goodness of fit test are often better. For testing the equality of variance, an F-test may be better.

Put something heavy but small enough to fit on the heads side and throw it high up in the air so that it has time for the heads side to face downward and the tails side upward.

If you pick enough cards, without replacement, the probability is 1.

The probability for a single random draw is 1/26.

If you disregard the sequence of outcomes, there are 6 possible outcomes:

0H 5T

1H 4T

2H 3T

3H 2T

4H 1T and

5H 0T

If not, there are 25 = 32 outcomes: TTTTT, TTTTH, TTTHT etc.

There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the required probability is 0.3126.

4(13c4)(39c1) = (4)(715)(39)=1,11,540

if u wereood at math it wouldnt be

There is insufficient information in the question to properly answer it. In order to compute a Z score from a raw score, you need the mean and the the standard deviation, neither of which was given. Please restate the question.

There are 36 permutations of two dice. Only one of them has a sum of two. Then probability, then, of rolling a sum of more than two is 35 in 36, or about 0.9722.

The number of permutations of the letters in PREALGEBRA is the same as the number of permutations of 10 things taken 10 at a time, which is 3,628,800. However, since the letters R, E, and A, are repeated, R=2, E=2, A=2, you must divide that by 2, and 2, and 2 (for a product of 8) to determine the number of distinctpermutations, which is 453,600.

8/52

Since there are four 4's in the deck, and 13 club's, one of which is a four, the probability of getting a 4 or a club in a standard 52 card deck is (4 + 13 - 1) in 52, or 16 in 52, or 4 in 13, or about 0.3077.

probability of a machine component failing = 2/7

P(at least 4 failed) = P( 4 failed)+P(5 failed) +P(6 failed)+P(7 failed)

Using binomial probability:

P(4 failed ) =7C4 (2/7)^4 ((5/7)^3 = 0.084987

P(5 failed) = 7C5 (2/7)^5 (5/7)^2 = 0.020395

P(6 failed ) = 7C6 (2/7)^6 (5/7) = 0.002719

P(7 failed) = (2/7)^7 = 0.000155

Adding, P(at least 4 failures) = 0.108257

Because there is billions of people, and only 365 days for their birthdays to be spread over.

Probably a 1% chance, haha. You shouldnt expect it if there wasn't a huge incident or sickness going around. Even if there IS a disease or flu, the most people missing in your class should be around 1-45%.

So dont get ur hopes up ;D

Theoretical probability is the probability of something occurring when the math is done out on paper or 'in theory' such as the chance of rolling a six sided dice and getting a 2 is 1/6. Experimental probability is what actually occurs during an experiment trying to determine the probability of something. If a six sided dice is rolled ten times and the results are as follows 5,2,6,2,5,3,1,4,6,1 then the probability of rolling a 2 is 1/3. The law of large numbers states the more a probability experiment is preformed the closer to the theoretical probability the results will be.

rolling 8 on a 6 sided dice? in a single roll? approximately 0.

on a 12 sided dice? one in 12.

two six sided dice? 5/36

There are 36 permutations of two dice. Of these, 6 have a sum less than five, 1+1, 1+2, 1+3, 2+1, 2+2, and 3+1. The probability, then, of rolling a sum less than five on two dice is 6 in 36, or 1 in 6, or about 0.1667.

Identical twins would have the most genetic similarities, since they share the same original 46 chromosomes.

There are 2 possible answers. If you meant is either one of the dice land on a 1,

then the answer is 1/3. If you meant if they both ADD UP to 1, then it is impossible

and the answer is 0.

===========================================

The first answer accurately states the theoretical probabilities. But the question

clearly specifies "the experimental probability". That number is the result of an

experiment which, as far as we know, has not yet been perfrormed.

Also, in the parlance of frequent rollers, "rolling a (x)" means a roll of two dice

after which the sum of the spots showing on the top surfaces of both is (x).

If you are poor, 10 - If you are wealthy, 50. (including me)