Statistics

88 + 8/8 = 89

The sample space of a standard six sided die rolled twice, or two dice rolled once (they are the same) is [11, 12, 13, 14, 15, 16, 21, 22, 23, 24, 25, 26, 31, 32, 33, 34, 35, 36, 41, 42, 43, 44, 45, 46, 51, 52, 53, 54, 55, 56, 61, 62, 63, 64, 65, 66].

states and cities of hometowns of members of an organizations

Some disadvantages: Cannot be used for categorical data. Difficult with large number of observations. Not very good if there are many stems with no leaves (you must show bare stems). This can be a problem if there are outliers. Ideally require leaves to be ordered on each stem - hard work. Tricky to use (though not impossible) if decimal stem/leaf are not the optimal solution.

If you multiply your number by any number greater than 1, the result will be greater than the starting number - assuming your number is positive. If your number is negative, you need to multiply it by any number less than 1, to get a result that is greater than the original number.

To get a number that is slightly greater, multiply by a number that is slightly greater than 1 (ot slightly lee than= -1).

By the definition of standard deviation, 95.46% of the normal population will be within 2 SD of the mean.

Explanation: The normal distribution of a population means it follows the "bell curve". The center of this bell curve is the population's mean value. One standard deviation defines two areas (on the left and right side of the central "mean" value) under the bell curve that each have 34.13% of the population. The next standard deviation adds two additional areas under the curve, each having 13.6% of the population. Adding the areas under the curves on both sides gives us (34.13% + 13.6%) x 2 = 95.46%

To determine how many numbers have a sum of digits equal to nine, we consider the possible combinations of digits that add up to nine. These combinations include (9,0), (8,1), (7,2), (6,3), and (5,4). Therefore, there are five possible combinations of digits that sum up to nine.

There are a couple different types of balance scales. For a triple beam balance, balance the scale, place item in the pan, move the sliders starting with the largest, adjust weight to zero, and add the riders for the total weight. For a one-pan scale, place item in one pan, estimate, place mass on free end until even, then add the masses for the total weight.

Research shows that not all individuals who have experienced abuse in childhood will go on to become abusers themselves. However, there is a correlation between childhood abuse and later perpetration of abuse. Studies suggest that around 30% to 40% of individuals who have been abused may become abusers later in life. It is important to note that this percentage can vary based on individual factors, such as access to support services and therapy.

999,999,999 if you don't include 000000000, otherwise 1,000,000,000.

If you don't allow repeated digits then 9 factorial, ie 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 = 362,880.

Well, isn't that a happy little math problem! Two thirds of 70 is like painting a beautiful picture with numbers. Simply divide 70 by 3 to get 23.33, then multiply that by 2 to get 46.67. So, two thirds of 70 is 46.67. Just remember, there are no mistakes in math, only happy little accidents.

Well, isn't that just a happy little mystery we have here! Let's take a closer look at our clues. If the tens digit is half the hundreds digit and the sum of the digits is 9, we can see that the hundreds digit must be 6, the tens digit is 3, and the units digit is 0. So the missing number X is 630. Happy solving, my friend!

0, 1, 2, 3, 4, 5, 6, 7,.......101, 102, 103, 104, 105, 1001, 1002, 1003, 1004, 1005,........ 5001, 5002, 5003, 5004, 5005,.......9996, 9997, 9998, 9999

If it MUST be all four digits then the first thousand would just be changed to 0000, 0001, 0002, 0003 and so on.

Inferential statistical methods are used when data is collected from a sample in the population. Inferential statistics are used to generalize the results of the sample to the population. In a census you have data from each and every member of the population, so you just use descriptive statistics.

'Stuck' ???? Well lightning might stick you to the ground.

I think you mean 'struck'.

In a house, building, or a car, the probablity is very low.

However, on an open hillside/prairie the probability is much higher, because you are above the surrounding surface, and you act as a lightning antenna/conductor. Hence a strike us far more probable.

Adding doubles can help you multiply by 2 through the property of commutativity in multiplication. By adding two equal numbers together (doubles), you are essentially multiplying one of the numbers by 2. For example, 5 + 5 = 10, which is the same as 5 x 2 = 10. This strategy can simplify multiplication problems and help build a deeper understanding of the relationship between addition and multiplication.

-123456785

In Pascal's Triangle, each number is the sum of the two numbers directly above it. Row 13 in Pascal's Triangle would start with the number 1, followed by the numbers 13, 78, 286, 715, 1287, 1716, 1716, 1287, 715, 286, 78, 13, and finally 1. These numbers represent the coefficients of the terms in the expansion of (a + b)^13.

There are 100 in the 400s.

In the 100s, 200s, and 300s, the ones place or the tens place could be 4. There are 10 numbers with a 4 in the ones place in each 100. There are 10 numbers with a 4 in the tens place in each 100. There is one overlap where there is a 4 in both the tens and the ones place. So, there are 19 numbers with a 4 as a digit in the each 100.

Therefore, there are (19 x 3) + 100 = 157 numbers with a 4 as one of the digits.

Here are the numbers in the 100s with a 4 in the ones place:

104

114

124

134

144

154

164

174

184

194

Here are the numbers in the 100s with a 4 in the tens place:

140

141

142

143

144

145

146

147

148

149

These lists have 20 numbers, but 144 is duplicated, so there are 19 numbers with 4 as a digit. The same will apply to the 200s and 300s. There will be a 4 in every number in the 400s, since the hundreds digit will always be a 4.

Working only with positive numbers*, any of the following would do.

1 + 47

2 + 46

3 + 45

4 + 44

5 + 43

6 + 42

7 + 41

8 + 40

9 + 39

10 + 38

11 + 37

12 + 36

13 + 35

14 + 34

15 + 33

16 + 32

17 + 31

18 + 30

19 + 29

20 + 28

21 + 27

22 + 26

23 + 25

24 + 24

* if negative numbers are allowed then there is an infinite range

49 - 1

50 - 2

51 - 3

... and so on in an endless sequence adding 1 to each value.

The median is the middle number of a set of numbers. But because there are ten numbers in this case you can't have a middle one.

Sometimes in this case people will use the mean which is the sum of the list divided by the number of items in the list.

Using this method the median is 28.5

if the question is how many 5/6 are in 3 then you would use the following calcuation: if 3 = 18/6 then 18/6 divided by 5/6 could also be stated as 18/6 times 6/5 (18 times 6) divided by (6 times 5) (108) divided by (30) 108/30 simplified = 36/10 = 18/5 18/5 is also 3.6

To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.