Statistics

(1/2)3 = 1/8.

Perpendicular.?

Here's one way to do it:

#include <stdio.h>

int main(int argc, char *argv[]){

int n;

for( n = 1; n < 100; n++){

if(n % 10 == 1) printf("%i ", n);

}

return 0;

}

And here's a more efficient way to do it:

#include <stdio.h>

int main(int argc, char *argv[]){

int n;

for( n = 1; n < 100; n += 10){

printf("%i ", n);

}

return 0;

}

The product of 36 (= 9 X 4) by any integer will be integrally divisible by both 4 and 9. The smallest integer by which 36 can be multiplied to yield a product with five digits is 278, for which the product is 10,008. The largest integer by which 36 can be multiplied to yield a product with no more than five digits is 2777, for which the product is 99,972. Therefore, the product of 36 multiplied by any integer from 278 to 2777, inclusive, satisfies the requirements stated in the problem. 36,000 and 46,656 are examples.

Assuming you can't repeat the numbers, there are:

56*55*54*53*52 = 458,377,920 permutations.

If order doesn't matter (as in a lottery ticket), there are:

(56*55*54*53*52)/(5*4*3*2*1) = 3,819,816 combinations.

No. The range is the maximum value less the minimum value. If all the values are different, the maximum must be different from the minimum. Consequently, the max minus min must be greater than zero.

The total marbles are 60, your mathematical expectation of getting a single blue marble in one try is therefore 17/60. If you grab 7 random marbles, the mathematical expectation is 7 times 17/60. This is the expectation, in an actual experiment you will get more or less than that, but it should be fairly close to the calculated value. (Note that the mathematical expectation in this case isn't even an integer.)

7,9,10,11,13 Assume the data list from smallest to largest is A,B,C,D,E. Then from the info given C=10 since 10 is the median. Also the range of the data is 6, so that means that E-A = 6. Since the mean of the data is 10 then (A+B+C+D+E)/5 = 10 or A+B+C+D+E = 50 You can substitute the value for C and E = 6+A (since the range is 6) to get A+B+10+D+(6+A) = 50 or simplified: 2A + B + D =34 Now since the median of the data is 10 the value of B will be less than 10 and A will be less than B. The value of D will be greater than 10 and E will be greater than D. To figure out the data list use trial and error. Start by picking a value of D > 10. Start with 11. From the equation above you have 2A + B + 11 = 34, now pick a value of B < 10. Start with 9 and substitute to solve for A. 2A + 9 + 11 = 34 or 2A = 14 and A=7 So A=7, B=9, C=10, D=11 and E=6+A or 13. To check see if these numbers equal the mean of 50. (7+9+10+11+13)/5 and it does. If it didn't work then you'd have to go back and pick values of B, D again until it does. Hope that helps.

Yes, it can.

When you get this kind of statistic for sample data, the best you can say is that this is an estimate of r for the whole population. Different data from the same population, however carefully collected, will almost certainly not produce a value of r exactly equal to the original one. But if sampling is done carefully, then many samples will allow you to estimate values that are closer and closer to the 'true' value for the population.

Even then, you cannot be sure, depending on the nature of the variables themselves and how they directly interact (if at all) that r will always be close to your best estimate of its value. Other factors may cause radical and unexpected changes in its value. This is so in part because r cannot by itself be used to indicate a cause/effect relationship between the variables.

Yes, they do.

50 - 50

Not by itself. In the sequence 80, 82, 95, 100, 106... 95 is the median.

three, because for one third three was the denominator , and for one sixth the denominator was devisable by three.

9

He was exiled to St Helena.

The range is the difference between the largest number, 10, and the smallest number, 1. So the range is 9.

Only one selected 68%

Assuming digits may not be repeated, there are 10C4 = 10*9*8*7/(4*3*2*1) = 210 of them and I regret that I am not minded to go through the list.

24

99999

There are 26 different ways of selecting a black card from a standard deck of 52 cards.

It does not have any solutions! 14.8 is a number, not an equation, inequality or question and so has no solutions.