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What is memory word size required in an 8085 system?
In an 8085 system, the memory word size required is 8 bits. This means that each memory location can store 8 bits or one byte of data. The 8085 processor accesses memory locations using these 8-bit memory addresses to read or write data during program execution. The memory word size of 8 bits allows the 8085 system to handle data in small, manageable chunks efficiently.
How many memory location can be addressed by microprocessor 8085?
The 8085 can address 216, or 65536 different memory locations.
What is slow memory interfacing?
explain how slow memory get interfaced with 8085
How many machine cycles requires to complete the execute IN 84H in 8085?
The instruction IN 84H in the 8085 microprocessor requires 5 machine cycles to complete. This includes 1 opcode fetch cycle and 4 memory read cycles. The opcode fetch retrieves the instruction from memory, while the read cycles are used to read the data from the specified input port.
Which is used to connect low memory in 8085?
READY
The minimum ICs required for 8085 to start working properly?
the minimum number ICs required for 8085 to start working properly are 3
What is memory word addressing capability of 8085 µp?
64K
IN 8085 local variables will get stored in?
Registers or RAM-memory.
What is memory address register of Intel 8085?
8 bits
How many memory address can by address by 8085?
64 kb
How much maximum memory size that 8085 can access?
The 8085 microprocessor is an 8-bit processor with a 16-bit address bus. This means it can access a maximum of 64 KB (2^16) of memory. The 8085 can address memory locations from 0000H to FFFFH, totaling 64 KB of memory space. This limitation is due to the 16-bit address bus, which can only address up to 64 KB of memory.
Why memory capacity of 8085 mp is 64 KB?
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
