An alpha particle consists of 4 nucleons, which are 2 protons and 2 neutrons.
In alpha decay, an alpha particle is emitted from the nucleus of an atom, so the atom loses 2 protons, and a total of 4 nucleons.
The atomic number of an atom undergoing alpha decay is reduced by 2, the number of protons lost, and the mass number is reduced by 4, the number of nucleons lost.
Alpha decay is represented as
ZXA(parent) ------>Z-2YA-4(daughter) + 2He4 (alpha particle) + Q
Where Z = atomic number, A = Mass number and Q represents energy released as a result of mass defect in the decay.
Beta- involves the transformation of a neutron into a proton, so the atomic number will go up by one, while the Atomic Mass number stays the same.
6C14 -> beta-, t1/2 = 5730 years -> 7N14 + e- + v-e
Beta+ involves the transformation of a proton into a neutron, so the atomic number will go down by one, while the atomic mass number stays the same.
6C11 -> beta+, t1/2 = 20.3 minutes -> 5B11 + e+ + ve
A general equation is:
Polonium-x---------------alpha-----------Lead-y,
where x is an isotope of polonium and y is an isotope of lead.
225Ac---------α-----→221Fr (half-life = 10 days)
88Ra223 ---> 86Rn219 + 2He4
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When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
148/64 Gd ---> 144/62 Sm + 4/2 He (apple executive)
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
This would be the alpha particle. An alpha particle has two neutrons and two protons, and it's actually a helium-4 nucleus. That's why we write this particle like this: 42He or He+2 Use the links below for more information.
The alpha decay of protactinium-231 will result in the appearance of actinium-227. It might look like this if we wrote it out: 91231Pa => 24He + 89227Ac The alpha particle is a helium-4 nucleus, so we write it that way.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Po-216- -----------------> Pb-212
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
The equation for the alpha decay of 234U is: 92234U --> 90230Th + 24He representing the alpha particle as a helium nucleus. 234U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
lithium
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
148/64 Gd ---> 144/62 Sm + 4/2 He (apple executive)
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
For nuclear decay, you must also specify what isotope you are talking about. Just saying "Sulfur" simply isn't enough information.
This would be the alpha particle. An alpha particle has two neutrons and two protons, and it's actually a helium-4 nucleus. That's why we write this particle like this: 42He or He+2 Use the links below for more information.