for three phase the calculation is 30,000 = 1.73*V*I - simple as that.
For single Phase the calculation is 30,000 = V*I - simple as that
It is important to note the voltage in the first line is Line to Line (typically how it is specified in three phase power systems), and the second line it is Line to neutral.
A 30KVA transformer is the same as 30,000VA to find out the Amps you need to divide the voltage if the transformer is single phase for example:
30,000VA / 480V = 62.5 Amps
The calculation for a 3 phase transformer is the VA / voltage / 1.73 for example:
30,000VA /480V / 1.73 = 36.12 Amps
The equation that you are looking for is; Amps when Kilowatts is known - kW x 1000/1.73 x volts x pf. Usually the power factor of a transformer is about .9.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
It depends on the incoming primary voltage. For a 5kva utility transformer receiving 15,000 volts on the primary the current drawn would be one third of one amp to give you an output of 5,000 VA (watts). Just remember this, volts x amps = watts or volt amps.
2.083 amps
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
That gives you 18.5 amps.
kVA = 1000va Therefore 1000/220 Answer 4.54A
160 amps at 12v.
160 amps at 12v.
You have your own answer. It is 1.5 amps.
480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.