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25.0 g C10H8N2O2S2 ( 1 mole C10H8N2O2S2/252.324 g)(10 mole C/1 mole C10H8N2O2S2)(6.022 X 1023/1 mole C)

= 5.97 X 1023 atoms of carbon

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Q: How many atoms of carbon are in 25.0 grams of dipyrithione?
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