How many grams of H2O will be produced from 32.0 grams of O2?

Answer 1

Start with the balanced equation of the formation of water:

2 H2 + O2 --> 2 H2O

It takes one mole of oxygen to produce 2 moles of water.

32.0 g O2 * (1 mol O2/32.00 g O2) * (2 mol H2O/1 mol O2) * (18.02 g H2O/1 mol H2O) = 36.04 g

Therefore, about 36.04 grams of water will be produced from 32.0 grams of oxygen gas, assuming that it can react with unlimited amounts of hydrogen gas.

Answer 2

To the justified number of significant digits, the masses given correspond to one mole of diatomic oxygen and two moles of diatomic hydrogen. The formula of water is H2O; therefore, these numbers of moles produce two moles of water molecules, and the number of the latter is twice Avogadro's number = 1.2 X 1024.

Answer 3

32g of oxygen is 2 moles oxygen (O) atoms. To make this react completely you require 4 moles of hydrogen (H) atoms which weighs 4g.

Added:

Not by atoms but by molecules, like the balanced equation will give:

O2 + 2H2 --> 2H2O

Reactant [O2:H2] molecular ratio = reactant molar ratio = 1 : 2

O2 = 32 g O2 = 32g / (2*16.0) g/mol O2 = 1.0 mol O2

2H2 = 2.0 mol H2 = 2.0 * (2*1.008) g/mol H2 = 4.03 = 4.0 g H2

Answer 4

36 grams of water

Answer 5

8 grams

Answer 6

4

Answer 7

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