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3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STP

apex- 0.125 moles

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Q: How many moles of air are there in a 3 l container at 1 ATM pressure and 293 k?
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How many moles of air are there in a 3 L container at 1 ATM pressure of 293 K?

0,125 moles


How many molecules are in 3 moles of carbon dioxide?

1 mole is 6.022 141 293 x 1023 molecules. (Avogadro's constant). If you have 3 moles of CO2, then you have 3 x 6.022 141 293 x 1023 molecules = 1.806642388 x 1024 molecules!


How many moles are there in a sample of gas held in a 0.325 liter container at 0.914 ATM and 19 deg Celsius?

1 mole (mol) of gas occupies a volume of 22.4 L at a temperature of 20 deg C and pressure of 1 ATMIn 0.325 L there will be only (0.325 / 22.4) molAt 0.914 ATM there will be only 0.914 of the number of moles that would be present at 1 ATMAt 19 deg C (292 deg Absolute or Kelvin) there will be (293 / 292) the number of moles that would be present at the standard temperature of 20 deg CTherefore the number of moles= (0.325 / 22.4) x 0.914 x (293 / 292)= 0.0133 mol


Explain why the molar volume of a gas at RTP is greater than that of the gas at STP?

At RTP the assumed temperature is 293ºK, at STP the assumed temperature is 273ºK. The formula used for this is Pressure x Volume = moles x ideal gas constant x Temperature. So Volume = (moles x ideal gas constant x temperature) / Pressure Assuming Pressure and moles stays constant... Volume at RTP = ( 1 mole x 8.31451 x 293 K ) / ( 101.325 Pa) Volume at RTP = 24.0429 Volume at RTP = 24.0dm^3 Volume at STP = ( 1 mole * 8.31451 * 273 K ) / ( 101.325 Pa) Volume at STP = 22.4017 Volume at STP = 22.4dm^3


What is the pressure exerted by 1.2 mol of a gas with a temperature of 20 C and volume of 9.5L?

In this case, pressure is calculated based on the temperature at kelvin, so 16 Celsius is 289 kelvin. Then, you multiply the moles by the dm^3*kPa (in this case 8.31 dm^3*kPa, multiply that by the temperature, and divide by the volume, to get 162 kPa.