if you have 100 liters how many moles does that equal?
1 Liter of water equals 1000g or 1kg
54,0 grams of water is equivalent to 3 moles.
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
75 grams water is equal to 4,166 moles.
2.35 grams water (1 mole H2O/18.016 grams) = 0.130 moles water ===============
1 Liter of water equals 1000g or 1kg
180 grams of water is 10 moles of water.
54,0 grams of water is equivalent to 3 moles.
1 litre of water weighs 1000 grammes.
it equals exactly 2000 things that equals another thing which also equals another thing. there hope this helped bye :P
0.34 grams water (1 mole H2O/18.016 grams) = 0.02 moles water ==============
75 grams water is equal to 4,166 moles.
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
1 mole equals 6.022 x 10 to the 23 molecules