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When resistors are connected in series, the flow of current through them is the same. This means that the current passing through each resistor is equal, as it has to pass through each resistor in the series circuit.
A multimeter set to measure current (in amperes or milliamperes) would be connected in series to the resistor to measure the current flowing through it. The multimeter would be placed in series with the resistor to accurately measure the current passing through it.
1amp
This circuit is a series circuit, as the current flows sequentially through resistor 1, then through resistor 2, before returning to the battery. The same current passes through both resistors, and the total resistance is the sum of their individual resistances. The voltage across the circuit is divided between the two resistors according to their resistance values. Additionally, if one resistor fails, the entire circuit will be interrupted, stopping the current flow.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
All the way along when the crocodile clip is connected to a resistor, when the other end of the resistor is connected to the other side of the battery.
RTL logic: NPN transistor. Emitter grounded. Input connected to base through a resistor. Vcc also connected to base through a resistor. If the input is high or open, the transistor is on. If the input is low, the transistor is off. Connect a resistor from Vcc to the collector. The collector is the ouput. You have to play around with resistor values to setup your fan-in and fan-out properties.
True
12 milliamps
E/R=I. 100/50=2 amps.
as the given cells have the same current flowing in through them (current flowing through the cells connected in series is equal to the current flowing when connected in parallel ) equate the formula's of cells connected in series and cells connected in parallel.thus by equating we get the value of the internal resistor as 2 ohms.
Use the equation V = I * R 20 = I * 5000 I = 20 / 5000 I = 0.004 Amps The answer to your question is 4 mA of current will flow through the resistor.