take the pea plant that produces round seeds and self pollinate it. if in the f1 progeny or in the next filial generation all the plants produce round seeds then it is a homozygous plant and if some seeds are round whereas some are wrinkled then the plant is heterozygous.
round seeds are a dominant phenotype therefore a pea plant with round seeds could be either (R/r) or (R/R)
in order to test whether the plant is homozygous dominant or heterozygous cross the plant with a true-breeding wrinkly seeded plant, as wrinkly seeds are the recessive allele for this gene
therefore
(R/r) x (r/r) = 2/4 round seeds + 2/4 wrinkly seeds
(R/R) x (r/r) = 4/4 round seeds
depending on the results you achieve you'll known whether the plant is heterozygous or homozygous dominant
The expected genotypic ratio is 2RR:2Rr. All of the offspring should have the round phenotype.
Suppose that, in a pea plant, round seeds are dominant over wrinkled seeds in the "texture" gene. If you were to take two plants heterozygous for the texture gene and cross them together to make eight new plants, how many of those plants should express the smooth phenotype? Use a Punnett's Square to determine the results.
25%
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
Worms will not eat your plant but their circulation round the pot will disturb the rootball and cause the plant problems.r
An example of incomplete dominance in humans is nose size. If you cross a person with a large nose, with someone with a small nose then the child may have a medium nose. This happens because neither trait dominates the other.
2
2
The possible phenotypes are tall and round, tall and oval, short and round, and short and oval. Genes don't affect other genes during reproduction.
In pea plants round seeds are dominant to wrinkled. So to have round seeds you either will have two dominant alleles (homozygous dominant) or one dominant and one recessive allele (heterozygous)
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
75% 3/4 chance of it being square. 25% 1/4 change of it being round.
Pill imprint 315 has been identified as Vytorin 10 mg / 80 mg.Vytorin is used in the treatment of high cholesterol; high cholesterol, familial heterozygous; high cholesterol, familial homozygous and belongs to the drug class antihyperlipidemic combinations.
It is a 75% chance that the seeds will be round.
Suppose that, in a pea plant, round seeds are dominant over wrinkled seeds in the "texture" gene. If you were to take two plants heterozygous for the texture gene and cross them together to make eight new plants, how many of those plants should express the smooth phenotype? Use a Punnett's Square to determine the results.
When the radish is heterzygous for shape The radish is oval.
25%
Monohybrid - A genetic cross made to examine the distribution of one specific set of alleles in the resulting offspringExample: tall peas x short peas or TT x ttDihybrid - Hybridization using two traits with two alleles each.Example: tall peas with round seeds x short peas with wrinkled seeds or TTRR x ttrr