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Calculate the molarity of 18.0 grams of H2SO4 in 2.00 L of solution?
Wiki User
∙ 14y ago
Firstly, the moles of sufluric acid: n=? n=m/M
m=18g = (18)/(98.086)
M=98.086 =.18mol
Thefore, there is .18mol per 2 litre (18g in 2L)
Therefore, its molarity is .09mol/L
Wiki User
∙ 14y ago
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