It is called strcmp, part of the standard run-time library. Returns 0 if the two strings are equals, non-zero otherwise.
The most efficient way to swap strings is to point at them, and swap the pointers. Swapping the actual strings is problematic if the strings are of unequal length but impossible when they are also statically allocated. Dynamic strings can always be physically swapped, however it's highly inefficient. If it really must be done, then use a built-in method such as string::swap(). Otherwise just use string pointers and swap the pointers, never the strings themselves. The following example shows how both techniques can be used on statically allocated strings. Example output is show below. #include <iostream> using namespace std; void SwapPointers(char ** pp1, char ** pp2 ) { cout<<"\nSwapping pointers:"<<endl; char * t = *pp1; *pp1 = *pp2; *pp2 = t; } void SwapStatics(char * String1, char * String2, size_t len) { cout<<"\nSwapping static strings:"<<endl; while(len--) String1[len]^=String2[len]^=String1[len]^=String2[len]; } int main() { char s1[] = "one "; char s2[] = "two "; char s3[] = "three "; // Note that the output statements before and after // swapping are exactly the same, proving the strings // have really swapped. cout<<"Original strings:"<<endl; cout<<s1<<s2<<s3<<endl; SwapStatics(s1,s2,sizeof(s1)); cout<<s1<<s2<<s3<<endl; cout<<endl; // We cannot swap s3 with either s1 or s2, because // s1 and s2 don't have the space to accomodate s3. // However, we can use pointers instead: char * p1 = s1; char * p2 = s2; char * p3 = s3; // Again, note that the output statements are the // same before and after swapping, proving the // pointers have swapped. cout<<"Original pointers:"<<endl; cout<<p1<<p2<<p3<<endl; SwapPointers(&p1,&p3); cout<<p1<<p2<<p3<<endl; cout<<endl; // Just to prove the strings didn't swap... cout<<"The strings have not swapped:"<<endl; cout<<s1<<s2<<s3<<endl; cout<<endl; return(0); } Output: Original strings: one two three Swapping static strings: two one three Original pointers: two one three Swapping pointers: three one two The strings have not swapped: two one three
swap (int *pa, int *pb) { *pa ^= *pb; *pa ^= *pa; *pa ^= *pb; }
Accessing data by address. Some data-structures, like lists and trees, are usually implemented using pointers.
you need strings to print any character(your name) this is not possible useing array:D
The String class includes two helpful methods: equals and compareTo.string1.equals(string2) will return true if the two strings contain the exact same charactersstring1.compareTo(string2) will return an int which describes the lexicographic relationship between the two strings. It will return a negative value if string1 is "less than" string2, a positive value if string1 is "greater than" string2, or zero if the two are equivalent strings.
nahi malum
mystrcpy (char* dest, char* src) { while ((*dest++ = *src++) != '\0); }
program to find maximum of two numbers using pointers
No.
sorry
Program below?!
i cant write
pro c language to implement linear search using pointers
System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");
The most efficient way to swap strings is to point at them, and swap the pointers. Swapping the actual strings is problematic if the strings are of unequal length but impossible when they are also statically allocated. Dynamic strings can always be physically swapped, however it's highly inefficient. If it really must be done, then use a built-in method such as string::swap(). Otherwise just use string pointers and swap the pointers, never the strings themselves. The following example shows how both techniques can be used on statically allocated strings. Example output is show below. #include <iostream> using namespace std; void SwapPointers(char ** pp1, char ** pp2 ) { cout<<"\nSwapping pointers:"<<endl; char * t = *pp1; *pp1 = *pp2; *pp2 = t; } void SwapStatics(char * String1, char * String2, size_t len) { cout<<"\nSwapping static strings:"<<endl; while(len--) String1[len]^=String2[len]^=String1[len]^=String2[len]; } int main() { char s1[] = "one "; char s2[] = "two "; char s3[] = "three "; // Note that the output statements before and after // swapping are exactly the same, proving the strings // have really swapped. cout<<"Original strings:"<<endl; cout<<s1<<s2<<s3<<endl; SwapStatics(s1,s2,sizeof(s1)); cout<<s1<<s2<<s3<<endl; cout<<endl; // We cannot swap s3 with either s1 or s2, because // s1 and s2 don't have the space to accomodate s3. // However, we can use pointers instead: char * p1 = s1; char * p2 = s2; char * p3 = s3; // Again, note that the output statements are the // same before and after swapping, proving the // pointers have swapped. cout<<"Original pointers:"<<endl; cout<<p1<<p2<<p3<<endl; SwapPointers(&p1,&p3); cout<<p1<<p2<<p3<<endl; cout<<endl; // Just to prove the strings didn't swap... cout<<"The strings have not swapped:"<<endl; cout<<s1<<s2<<s3<<endl; cout<<endl; return(0); } Output: Original strings: one two three Swapping static strings: two one three Original pointers: two one three Swapping pointers: three one two The strings have not swapped: two one three
pointers points to the memory address of another variable.....in functions we have two kind of variables the actual and dummy variable. when we operate on variables..the value of dummy variables are effected, but if we want to make changes in the actual variable then we have to refer to their address..and we can reach to address of the variables by only using pointers.
#include main() { //please read two strings int str1 and str2// while(str1[i]!='/0' &&str2[i]!='/0') if(str1[i]!=str2[i]) flag=1; if(flag==1) printf("equal"); } #include main() { //please read two strings int str1 and str2// while(str1[i]!='/0' &&str2[i]!='/0') if(str1[i]!=str2[i]) flag=1; if(flag==1) printf("equal"); }