0
The number of atoms in 1 gram of iron is Avogadro's number multiplied by 1/55.845 = 1022, to the justified number of significant digits This is not a small number by most people's standards!
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Which sample contains the same number of atoms as a gram atomic mass of he?
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
What is the number of atoms in 1 gram of iodine?
The answer is 4,745.10e21 atoms.
How many atoms are in a 341 g sample of scandium?
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
How many atoms are there in 42.0000 g of Au?
The gram atomic mass of Au is 196.967. Therefore, 42.0000 g contains 42.0000/196.92 or 0.213234 gram atoms of gold. The number of atoms is 0.213234 X Avogadro's Number or 1.28412 X 1023 atoms.
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
What is the number of atoms present in a 20 gram sample of Lithium?
1.7-10^24
Which sample contains the same number of atoms as a gram atomic mass of he?
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
What is the number of atoms in 1 gram of iodine?
The answer is 4,745.10e21 atoms.
How many atoms are in a 341 g sample of scandium?
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 1024 fluorine atoms?
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
What is the number of Cl- ions in 21.04 gram sample of AlCl3?
1 mol of AlCl3 has mass 133.5 g and has 3 mol Cl- atoms so 400.5 g AlCl3 means 3 mol AlCl3 which means 9 mol Cl- atoms. So Ans = 9 X 6.022 X 1023 = 5.4198 X 1024 Cl- atoms
How many atoms of lithium are in 18.7 g?
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
How many atoms are there in 42.0000 g of Au?
The gram atomic mass of Au is 196.967. Therefore, 42.0000 g contains 42.0000/196.92 or 0.213234 gram atoms of gold. The number of atoms is 0.213234 X Avogadro's Number or 1.28412 X 1023 atoms.
Which element Mo Se Na or Br contains the most moles of atoms in a 1.0 gram sample?
This element is sodium.
How many molecules of H2(g) are there in a 21.25 gram sample?
The number of molecules is 6,3985.10e24.
