Nitrogen is more electronegative than Hydrogen.
So +1 for each hydrogen and -3 for nitrogen
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
nitrogen is -3 H is plus 1
The assumed oxidation number of nitrogen in ammonia (3+) in this question, is wrongly signed:The correct oxidation number if nitrogen in NITRIDES (like in ammonia NH3, ammonium NH4+ and amino groups -NH2) is minus 3, so hydrogen has oxidation value of plus 1(one, like in H+) which is in fact the only possible form when attached to nonmetals.
the oxidation number of nitrogen is 5
oxidation number of I is -1. oxidation number of F is +1.
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
nitrogen is -3 H is plus 1
The assumed oxidation number of nitrogen in ammonia (3+) in this question, is wrongly signed:The correct oxidation number if nitrogen in NITRIDES (like in ammonia NH3, ammonium NH4+ and amino groups -NH2) is minus 3, so hydrogen has oxidation value of plus 1(one, like in H+) which is in fact the only possible form when attached to nonmetals.
It reacts with it. The reaction is a redx reaction. Nitrogen is reduced (its oxidation number goes from 0 to -3) and hydrogen is oxidised (its oxidation number goes from 0 to +1)
the oxidation number of nitrogen is 5
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number for H is +1, and the oxidation number for O is -1.
N has +3 state on it.Each H have -1 state.
fluorine oxidation number is -1
Oxidation number of o is -2. Oxidation number of H is +1.
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.