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Does the resistance of heater coil remains same when current flows through it?
Wiki User
∙ 11y ago
Typically resistance rises with temperature.
Wiki User
∙ 11y ago
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What is the voltage of a small electric heater if the heater is drawing 12 amperes and has a resistance of 10 ohms?
Voltage is current times resistance, 1.2 x 110 = 132 volts.
What is the voltage across an electric water heater element that has a resistance of 32 ohms when the current through it is 6.8A?
It is 6 times 8 and the answer is in volts.
If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same the heat produced by the heater will be what?
Since power is current times voltage, doubling current while keeping voltage the same will double the power. Ignoring slight non-linearity, if the power doubles, the heat will double.
Does heat come from the amps or the volts?
By driving current through a resistance, we create heat. But it takes voltage to drive current through a resistance. In that light, it takes both voltage and current to drive a resistance heater and get it hot. Power (watts) is current (amps) times voltage (volts). But power is also current squared (I2) times resistance (ohms), or I2R. Power is also voltage squared (E2) divided by resistance (ohms) or E2/R. To increase current through a given resistance (like a resistive heating element) you have to increase the voltage. Voltage, current and resistance are "locked" in a fixed arrangement called Ohm's law. It's a relationship that takes this form: E = I x R, or I = E/R, or R = E/I As power is amps times volts (P = I x E), we can answer the question asked here. Question: "Does heat come from the amps or the volts?" Answer: "Yes."
A 75 ohm light and a 150 ohm heater are connected in a parallel to a 150 volt power cource What is the total current through the circuit?
50 ohms...!
Does resistance of heater coil remains same when current flows through it?
Typically resistance rises with temperature.
Why does the cord of an electric heater not glow while the heating element does?
The heating element of an electric heater is a "resistor", the cord which conducts the electricity is not. The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes red hot and glows. On the other hand, the resistance of the cord is low. It does not become red hot when current flows through it.
If the current through a heater coil is 5 amp and the supply voltage is 120 volts the coil resistance is?
The formula you are looking for is R = E/I. Resistance = Volts/Amps.
Why are wires supplying electric current to the water heater thicker than those supplying current to the lights?
the water heater operates at high power compared to the lights and so the water heater requires a larger current. The wires supplying current to the water heater are thicker so that the wires have a low resistance. This reduces the risk of the wires overheating.
What is the current through the 150 ohm heater?
At 110 volts it is 0.8 amps. At 220 it is 0.4 amps. I=E/R. I=amps.E=volts R=resistance.
What is the voltage of a small electric heater if the heater is drawing 12 amperes and has a resistance of 10 ohms?
Voltage is current times resistance, 1.2 x 110 = 132 volts.
What is the voltage across an electric water heater element that has a resistance of 32 ohms when the current through it is 6.8A?
It is 6 times 8 and the answer is in volts.
If a 325 watt heater has a current of 6.0A what is the resistance?
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
Will a 110 electric heater produce the same amount of heat as a 220 heater at 1000 watts?
The load is a resistive load and as such it is governed by Ohm's law. Current is directly proportional to the voltage and inversely proportional to the resistance. As the voltage goes down so does the current. 2200 watt heater at 220 volts = 10 amps. R = E/I = 220/10 = 22 ohms of resistance in the heater. Now take the 2200 watt heater and using the same formula and at 110 volts. I = E/R, Amps = Volts / Resistance. 110/22 = 5 amps. As you can see ohm's law holds true, the current is inversely proportional to the resistance and as the voltage goes down so does the current. To answer the question, yes a 220 volt heater will run on a 110 volt circuit but at a reduced wattage. W = A x V = 5 x 110 = 550 watts.A 2200 watt heater at 220 volts would draw 1/2 the current of a 2200 watt heater at 110 volts.A 2200 watt heater at 220 volts is 22 ohms of resistance. Resistance would not change with the voltage, current would only be 5 amps (a resistor is a current limiter, it will only let more current through if you apply more voltage not less); but the wattage would only be 550 watts. This would only give you a fourth of the power this heater was designed for! The heater and the wires would have less heat.
How much current will an electric heater draw from a 110-volt line if the resistance of the heater when hot is 26.7 ohm?
4.12A. V=IR
If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same the heat produced by the heater will be what?
Since power is current times voltage, doubling current while keeping voltage the same will double the power. Ignoring slight non-linearity, if the power doubles, the heat will double.
The cord of an electric oven does not glow while the heating element glows.Why?
The cord is manufactured to have as low a resistance as possible, while the heating element is intentionally manufactured with a carefully controlled resistance. The current through the whole loop ... cord plus heater ... is determined by the resistance of the whole loop. The magnitude of the current 'I' is (E/R) ... E = the utility line voltage, R = resistance of the cord+heater. But the power dissipated by each individual resistance in the loop is proportional to the resistance of that section. P = I2R. So the heating element dissipates more power than the low-resistance line-cord does.
