Descriptive and Inferential:
Descriptive statistics describe the data set.
Inferential statistics use the data to draw conclusions about the population.
No matter what fraction one gives, there is one closer. There is no answer to this question.
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because they can help you find your right answer
90, 91,92,93,94,95,96,97,98,99,100.
There are eleven terms. To find the median, you take the absolute middle term.
The absolute middle term is '95'.
NB You will notice that there are five terms to the left of 95, and five terms to the right of 95.
The naive answer to the question is 30. That assumes that the observations are more or less uniformly distributed across the range and, if that is the case, you should get around 5 observations per class.
It also assumes that your interest in the observations is uniform: you are as interested in values near 60 as you are in values near 480. If you were only really interested in values above 450, you could class all of 56 to 449 in one big class and split the rest into smaller classes.
It is also important to see if the distribution is uniform. If it is skewed in either direction, it would make more sense to have smaller classes where the observations were more dense and wider classes where they were sparse.
All the numbers from 000 to 999 (inclusive).
T-distributions tend to be flatter and more spread out than normal distributions due to their heavier tails. Unlike the normal distribution, which has thin tails, t-distributions account for uncertainty in sample variance estimation, making them more robust for smaller sample sizes. The additional variability inherent in t-distributions arises from the incorporation of the sample size through the degrees of freedom parameter. As the degrees of freedom decrease, the t-distribution becomes more spread out and flatter, reflecting increased uncertainty and variability in the estimates. This property makes t-distributions well-suited for inferential statistics, particularly when dealing with small sample sizes.
sample space
The probability is
(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n
Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1)
= 10*9*8*7/(4*3*2*1) = 210
First of all place the numbers in rank order. Hence
46,57,68,72,72,93.
RANGE; is the difference between the highest and lowest numbers, which is 93-46 = 47
MEDIAN: is the absolute mid-point. Since there is no absolute mid-point, we take the two middle numbers , add them and divide by '2'. Hence. ( 68+72)/2 = 70
MODE: is the term that occurs most frequently. In this case '72'. as there are two of them , but only one each of the other terms.
MEAN; Add all the terms and divide by the number of terms.
(46+57+68+72+72+93) / 6 = 408/6 = 68
sqrt(900) = +/- 30
Remember , the inverse route.
30^2 = 30 x 30 = 900
or
(-30)^2 = -30 x -30 = (+)900
If the numbers are not allowed to repeat themselves then 362,880.
* * * * *
That is the number of permutations, not combinations.
In a combination the order of the digits does not matter. So there is only one 9-digit combination.