One nitrogen atom weighs 14.00674 u
1 u = 1.660538921(73)×10−27 kg
So... put simply:
14.00674 x 1.660538921(73)×10−27 kg
Working it out on Excel the nearest (it only goes up to 30 decimal places) I could get is this in kilograms, it's an approximate figure, I think the real figure is slightly higher.
0.000000000000000000000000002326 kg
Nitrogen is N2 and I mole would weigh 28 g
this second answer is correct, the first guy has no clue what he's talking about, so since nitrogen is diatomic, the formula for nitrogen gas will be N2 and the mass of one mole would be 28 grams, approximately
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
15 grams of nitrogen are equal to 1,071 moles.
550 g of nitrogen dioxide is equal to 11,94 moles.
The answer is 24,92 g nitrogen.
Clean dry air is composed of approximately 78% nitrogen by volume. Therefore, in 500 moles of clean dry air, the number of moles of nitrogen can be calculated as 0.78 x 500 moles, which equals 390 moles of nitrogen.
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
15 grams of nitrogen are equal to 1,071 moles.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
550 g of nitrogen dioxide is equal to 11,94 moles.
The answer is 24,92 g nitrogen.
For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NO=30.0 grams6.64 grams NO / (30.0 grams)= .221 moles NO
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
Clean dry air is composed of approximately 78% nitrogen by volume. Therefore, in 500 moles of clean dry air, the number of moles of nitrogen can be calculated as 0.78 x 500 moles, which equals 390 moles of nitrogen.
The number 2.20 moles of Sn equals 261.14 grams. This is a taught in biology.
To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.
The clarity of this question is not clear. I will assume grams and possibly moles as that number does not look like a number of atoms. Grams first, then moles. 4.0 X 102 grams quinine (1 moleC20H2N2O2/302.236 grams)(2 moles N/1 mole C20H2N2O2) = 2.6 moles nitrogen =============== Pretty much the same procedure if you meant moles just no dividing out a mass.