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The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
2,8 moles of calcium carbonate have 240,208 g.
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
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To make 1 mole carbon dioxide it takes 2 moles of HCl and one mole of Ca-carbonate.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
To determine the volume of carbon dioxide needed, you would need to know the stoichiometry of the reaction between carbon dioxide and calcium carbonate. In this case, since 20 grams of calcium carbonate is given, you would convert that to moles using the molar mass of calcium carbonate. Then, using the balanced equation, you can determine the mole ratio between carbon dioxide and calcium carbonate. Finally, using the molar volume of carbon dioxide gas at the given conditions (usually 22.4 L/mol at standard temperature and pressure), you can calculate the volume of carbon dioxide needed.
1400 grams
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
.06 moles