The formula for sodium chloride is NaCl. This means that for every one sodium ion, there is one chloride ion. The ratio is 1:1, so the numbers of each ion in a crystal of NaCl should be equal.
the structure of sodium chloride is in a lattice shape, and is described as having a giant ionic structure. each sodium ion is touched by 6 chloride ions. each chloride ion is touched by 6 sodium ions. here's a site with some pictures which will help you visualise the structure:
http://64.233.183.104/search?q=cache:cPw…
the structure of sodium chloride is in a lattice shape, and is described as having a giant ionic structure. each sodium ion is touched by 6 chloride ions.
The lattice of sodium chloride is face-centered cubic. The chloride ion is surrounded by six sodium cations.
Sodium chloride forms a lattice structure.
cubic
Compare the electronegativity of calcium to the electronegativity of chlorine. Find the number of electrons each will give up / accept. Balance the two. Calcium easily gives up two electrons. Chlorine easily accepts one electron.
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.
Chlorine can be involved in both ionic and covalent bonding. As it is a chloride, I would believe it to be a ionic bond, as a covalent bond would state the number of chloride atoms, e.g. dichloride.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
Zinc Chlorine2 hydrogen2
The chlorine in PbCl2 exists as chloride ions, and the oxidation number of chloride ions is always -1.
-1.
2
To convert the number of chloride atoms to mols of chlorine atoms, simply multiply by Avogadro's number. This number is 6.022E23. Note that chlorine typically exists as a diatomic molecule, consisting of two chlorine atoms.
Compare the electronegativity of calcium to the electronegativity of chlorine. Find the number of electrons each will give up / accept. Balance the two. Calcium easily gives up two electrons. Chlorine easily accepts one electron.
potassium=19 chlorine=17 potassium chloride=36
Since 35.5 is the approximate atomic mass of chlorine and each molecule contains two atoms of chlorine, the number of molecules is about half of Avogadro's Number, 3.01 X 1023.
Position on the periodic table is determined by the number of protons in the nucleus. This number is 17 for both neutral chlorine atoms and chloride anions. Because the chloride anion has one more electron than it has protons, the anion has one negative electrical charge.
Cl2 is the symbol of the diatomic neutral molecule of chlorine; the anion chloride is Cl-. The common valence of chlorine is -1.
chlorine atom has 17 electrons when it accepts one more it becomes chloride ion so chloride has total 18 electrons, isoelectronic with Argon.
Chloride ion like the chlorine atom has seventeen(17) protons. In an atom the number of protons and electrons is equal. However, in an ion the number of protons remains the same, BUT THE NUMBER OF ELECTRONS is different. So for chlorine atom there are 17 protons and 17 electrons. However, the chloride ion there are 17 protons and 18 electrons. This difference is indicated by 17(+) & 18(-) or (+)17 - 18 = -1 . So the chloride ion symbol is written as 'Cl^(-)'. The 'one' is never shown. NB A negative ion is given the name ' ANION;, NNB Do not confuse with 'Neutrons'. Different numbers of neutrons are referred to as ISOTOPES. Chlorine exhibits two principal isotopes. They are Chlorine-35 and Chlorine-37. Overall the proportions of these two isotpes is such that chlorine is given the atomic mass of 35.5. However, the number of protons remains the same at '17', and the number of electrons can still vary between the two isotopic atoms and ions.
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.