Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
Balance H2 plus N2 equals NH3
3H2 + N2 ----> 2NH3
4(NH3) + 5(O2) --> 4NO + 6(H20)
N2 + 3h2 -> 2nh3
4no2 + 6h20 -> 7o2 + 4nh3
2nh3+2h2o = 2no+5h2
N2o5 + h2o -------> 2hno3
N2 + 3h2 -> 2nh3
The net ionic equation is Zn + 2H+ --> Zn2+ + H2
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
H2 n2
2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O
Co2 + 3h2 gives ch3oh + h2o
(N2) + 3(H2) = 2(NH3)
Ammonia
2SO2 + O2 + 2H2O -------> 2H2SO4
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
This is a synthesis reaction.
2Na + 2H2O -> H2 + 2NaOH
H2 - hydrogen.
16,45 g nitrogen are needed.
2Na + 2H2O -------> 2NaOH + H2
The word equation for ammonia is 3 H2 + N2 → 2 NH3 (this is a balance equation) The formula (atom) is NH3 for ammonia
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
Mg + 2HCl = MgCl2 + H2 SO magnesium chloride and Hydrogen gas