Na and Zn are correct because they are elements. Na is monovalent so NaI is correct. Zn is divalent and so ZnI is incorrect and should be ZnI2 .
So if we have ZnI2 we need 2 Na to remove the I2 . So balanced it becomes:
2Na + ZnI2 ----> 2NaI + Zn
NaI is ionic as are all sodium (Na) compounds
Your question leads me to believe that you have the following equation: Na + Cl ---> NaCl2 In that case, note there is one Na (sodium) on the left and one on the right, so they are good. There's one chloride on the left but two on the right, so placing a "2" in FRONT of the Cl on the left will balance the equation and look as such: Na + 2Cl ---> NaCl2
4,1,2
CO32-(aq) + 2H+(aq) --> CO2(g) + H2O(l) (tribunated ions, Na+ and NO3-, are left out of the equation)
2HCl + Na(2)S-----> H(2)S + 2NaCl
na +i2
2Na+I2-->2NaI
Sodium + Iodine ----> Sodium Iodide2 Na + I2 ----> 2 NaI
3Na + PO4 ---> Na3PO4
2 Na + Br2 --> 2 NaBr
NaI is ionic as are all sodium (Na) compounds
Here is the balanced equation! TiCl4 + 2H2O --> TiO2 + 4HCl
Probably an N Dubz song
The chemical equation is:MgF2 + 2 Na = 2 NaF
2Na + 2H2O -> H2 + 2NaOH
2Na + 2 HNO3 = 2 NaNO3 + H2
Your question leads me to believe that you have the following equation: Na + Cl ---> NaCl2 In that case, note there is one Na (sodium) on the left and one on the right, so they are good. There's one chloride on the left but two on the right, so placing a "2" in FRONT of the Cl on the left will balance the equation and look as such: Na + 2Cl ---> NaCl2