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14 grams of nitrogen have 6.023 x 1023 atoms
So 2.2 grams will have (6.023 x 1023 x 2.2)/14 = 29.15 x 1023 atoms
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How many atoms are in 22 grams of argon?
Approx 3.32*10^23 atoms.
What is the mass in grams of 3.40x10 22 atoms He?
3.40 X 1022 atoms helium (1 mole He/6.022 X 1023)(4.003 grams/1 mole He) = 0.226 grams ===========
How many atoms of nitrogen are present in 1.00 g of nitrogen?
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
How many atoms are in a gold ring that has a mass of 19.7 grams?
Well, firstly you need to know if it is pure gold. Assuming that it is, convert the grams to moles 19.7g Au x 1molAu/197.0gAu = 0.1moles Au And then, to get the number of atoms in 0.1 moles of gold, multiply it by Avogadro's number, 6.22x10^23 atoms per mole 0.1mol Au x 6.22x10^23atoms/mole = 6.22x10^22
How many atoms are there in 5.10 grams of Phosphorus?
5.10 grams phosphorous (1 mole P/30.97 grams)(6.022 X 10^23/1 mole P) = 9.92 X 10^22 atoms of phosphorous
How many atoms are in 14 grams of Nitrogen?
the question is directing a discussion of Avagadro's number. If Nitrogen were an ideal gas ( it isn't) there would be 6,02 X 10 ^23 atoms
Is 15 grams of oxygen gas and 22 grams of nitrogen gas a mixture or a compound?
Mixture
How many atoms are in 22 grams of argon?
Approx 3.32*10^23 atoms.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen qnd 8 grams of oxygen form How many grams of water form?
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form.. How many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
What is the mass in grams of 3.40x10 22 atoms He?
3.40 X 1022 atoms helium (1 mole He/6.022 X 1023)(4.003 grams/1 mole He) = 0.226 grams ===========
How many nitrogen atoms are there in 7.5 g of CaNO32?
The species is; Ca(NO3)2 ( NO3(-) is a polyatomic ion and is in parenthesis ) 7.5 grams Ca(NO3)2 (1 mole Ca(NO3)2/164.1 grams)(2 mole N/1 mole Ca(NO3)2)(6.022 X 10^23/1 mole N) = 5.5 X 10^22 atoms of nitrogen
How many grams in 5.0x1022 molecules of nitrogen monoxide?
5.0 X 10^22 molecules of NO (1 mole NO/6.022 X 10^23)(30.01 grams/1 mole NO) = 2.5 grams of nitrogen monoxide
How many grams of nitrogen dioxide must react with water to produce 5.00x10 22 molecules of nitrogen monoxide?
11.5 g NO2
How many atoms of nitrogen are present in 1.00 g of nitrogen?
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
