5.0 X 10^22 molecules of NO (1 mole NO/6.022 X 10^23)(30.01 grams/1 mole NO)
= 2.5 grams of nitrogen monoxide
550 g of nitrogen dioxide is equal to 11,94 moles.
The nitrogen iodide is NI3.
15 grams of nitrogen are equal to 1,071 moles.
The density of O2 is 31.9988 grams per mole, meaning there are 0.143 grams and 4.47 mmols present. The density of NH3 is 17.0305 grams per mole, giving 4.09 mmols of ammonia. This means that they have approximately the same number of mmoles, thus the same number of molecules.
Negative balance
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
11.5 g NO2
550 g of nitrogen dioxide is equal to 11,94 moles.
7.5 x 10^23
The nitrogen iodide is NI3.
3.69 grams CO (1mol CO/28.01g CO )(6.022 X 10^23/1mol CO ) = 7.93 X 10^22 molecules
For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NO=30.0 grams6.64 grams NO / (30.0 grams)= .221 moles NO
15 grams of nitrogen are equal to 1,071 moles.
The density of O2 is 31.9988 grams per mole, meaning there are 0.143 grams and 4.47 mmols present. The density of NH3 is 17.0305 grams per mole, giving 4.09 mmols of ammonia. This means that they have approximately the same number of mmoles, thus the same number of molecules.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
Negative balance