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4,0 moles of the manganese contain 219,75 g.
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
its MnO4 that gives purple colour to the KMnO4 solution. MnO4 absorbs all the six colours present in the white light except for indigo and this colour reflects back to our eyes that is why we see it as purple coloured solution.
no MN does not get hurrincanes
I found some good ones in a gravel pit in little falls MN
manganese is a metal element. It shows +4 in Mno4 ompouund.
Permanganate is a poly atomic ion, not an element. It contains two elements: manganese (Mn) and oxygen (O). The formula of the permanganate ion is MnO4-
Molecular: Mn(O2)2empirical: MnO4
+7 for Mn -2 for each O
O.S. of Mn = +7 O.S. of O = -2 O.N. of cpd = -1
To balance the oxygens, you add H2O to one side, and the H^+ to the other (acid). Example:MnO4^- ===> Mn^2+ add 4 H2O to the right side MnO4^- ===> Mn^2+ + 4H2O this balances the oxygens. Now add 8H^+ to the left side MnO4^- + 8H^+ ===> Mn^2+ + 4H2O Now this is balanced for Mn, H and O. You now only have to balance the electrons (charge).
First start with what you know to find the total moles. Mn = 54.94g O = 16g 54.94g * 2 = 109.88g 16 * 3 = 48g Add these to get the weight of Mn2O3 which = 157.88 Divide 157.88 / 286 to get your total moles present, which = .552 Mols To find moles Mn, divide 54.94 by the total weight which is 157.88. This gives you your moles Mn, which is .348 mols. Since you have Mn2, multiply that number by 2 to get .695 mols Now you can divide Mol(Mn) by your total moles (.552) to get your moles Mn So .695 mol Mn2O3 / .552 mol Mn = 1.1 Mol Mn since 1.1 * 54.94 = 60 pct of the Molar Mass, this number makes sense since there is more Mn than O, the proportion seems correct. hope this helped! .
MnO4- turns into Mn+2.So purple change into pale pink.
The oxidation number of manganese in KMnO4 is 7+.
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
4,0 moles of the manganese contain 219,75 g.
4,0 moles of the manganese contain 219,75 g.