Because you asked how to make a 9 g/L solution of NaCl rather than a 9.0 g/L, or a 9.00 g/L solution, to make a 9 g/L solution of NaCl you first weigh out 9 g of dry NaCl. The weight, actually mass, of the NaCl needs to be 9 g plus or minus 1 g. Next, add the 9 g of NaCl to less than one liter of water, perhaps 25 or 50 mL less. Stir or shake the flask very well for several minutes after all of the NaCl has dissolved, then bring the total volume up to nearly 1 L. Stir or shake the flask very well again, then add water if necessary to ensure that the total volume is one liter.
To make a 9 grams per liter solution of NaCl, simply dissolve 9 grams of NaCl in enough water to make a total volume of 1 liter. Stir or shake the solution until the NaCl is completely dissolved. Measure the volume accurately using a graduated cylinder or volumetric flask.
A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
newtest3
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
26.8125 g
1.3g
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
The mass of NaCl is 14,61 g.
You need 841,536 g NaCl.
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
0.5 M means 0.5 moles per liter. so it depends on how many liters of solution that you need.Suppose you want to make 1 liter of solution, then you need 0.5 moles of NaClFrom the webelements.com Periodic Table:Atomic mass of Sodium (Na) = 22.990 & Atomic Mass of Chlorine (Cl) = 35.453So 1 mole of NaCl = (22.990 + 35.453) grams = 58.443 gramsBased on the 1 liter, we want to add 0.5 moles: (58.443 grams/mole)*(0.5 mole) = 29.2215 g (to make 1 liter of 0.5 M solution)
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl