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What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
Is mixing height is maximum in morning?
Sometimes. mixing height is maximum in afternoon
What is maximum ceiling height of an indoor shuttle court?
The height of a gymnasium is not typically standard. This means that different gyms will have different heights and dimensions.
What is the maximum height of scaffold?
120m
How does gravity affect a person's height or stature?
Does gravity affect a person's height and why?
When a football kicked reaches its maximum height how does its speed compare to its initial speed?
When it's at its maximum height its speed will be zero.
What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
A boy kicks a ball vertically upwards with an initial velocity of 12m/s. Calculate the time taken by the ball to reach the maximum hight and the maximum, height reached by the ball?
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
1 If you toss a ball upward with a certain velocity it falls freely and reaches a maximum height h What maximum height does the ball reach if you throw it upward with double the initial velocity?
If you throw the ball upward with double the initial velocity, it will reach a maximum height four times greater than the initial height. This is because the maximum height is directly proportional to the square of the initial velocity.
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
initial velocity of the kick = 28.06 m/s
What is the maximum height of a male to get into film industry?
There is no maximum height
If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
An object is thrown vertically upward when does it reach maximum height?
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
Is mixing height is maximum in morning?
Sometimes. mixing height is maximum in afternoon
A 0.50kg rock is launched upward with an initial speed of 80.0 meter per second how long will it take for he rock to reach its maximum height?
At the maximum height, the rock's final velocity will be 0 m/s. You can use the kinematic equation v_f = v_i + at to find the time it takes for the rock to reach its maximum height. Rearranging the equation to solve for time t, where a is the acceleration due to gravity, you can find the time it takes for the rock to reach its maximum height.
