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in the case of short-circuit the current is maximum hence the terminal potential is becomes zero
Somebody is trying a trick question! The electron that comes out of the negative terminal has zero potential energy. With respect to the positive terminal it has -1.5V of electrical potential energy, and so does every other electron at 0.0V whether or not they came out of the battery.
All cells have internal resistance. When connected to a load, the resulting load current results in an internal voltage drop across the internal resistance. This voltage drop acts in the opposite sense to the cell's e.m.f., thus causing its terminal voltage to fall below that of the e.m.f. The greater the load current, the greater the difference between the terminal voltage and the e.m.f.
The difference between terminal speed and terminal velocity is really simple. Terminal speed can be used to refer to the maximum speed an object can reach before factors like friction prevent anymore speed to be gained. Terminal velocity, however, generally refers to the rate at which this speed was gained.
Ideal Source
That's a difference in electrical potential, not potential energy.It's described in units of "volts".
Volts. Volts is another term for potential.
A terminal potential difference is the potential difference appearing across the terminals of a voltage source, such as a battery or a generator, which varies according to the load supplied.When the battery or generator is off load (i.e. no load is connected to it), the terminal potential difference is equal to the electromotive force of that battery or generator.The terminal potential difference tends to decrease as the load current increases, due to a corresponding increase in the internal voltage drop of the battery or generator.
Because they are connected in series. Lets say you have a flashlight that holds 2 D cell batteries. Each battery puts out 1.5 volts. Connect them in series and together they put out 3 volts. The flashlight is designed to run on 3 volts. A electronic device that uses 4 AA batteries is using 6 volts even though each battery is only putting out 1.5 volts. Connected in series you add to the voltage with the addition of each new battery.
When it is being loaded.
When the flashlight is ON , electrical current is flowing from one terminal of thebattery, through the light-bulb filament, to the other terminal of the battery.
"The potential difference between the terminals of a battery will equal the emf of the battery when there is no current in the battery. At this time, the current though, and hence the potential drop across the internal resistance is zero. This only happens when there is no load placed on the battery-that includes measuring the potential difference with a voltmeter! The terminal voltage will exceed the emf of the battery when current is driven backward through the battery, in at its positive terminal and out at its negative terminal." Raheel Ahmed Quaid i Azam University Islamabd Physics Dept
When a flash light is switched on the circuit between the lamp and the batteries is complete. When the circuit is complete, the electrons flow from the positive terminal of the batteries through the tungsten filament back to the negative terminal of the batteries. Once the electricity flows through the filament it starts glowing producing a bright light. When the the torch light is switched off the circuit is broken and the flow of electricity is disrupted switching off the light.
What is your question?
One terminal is positive and the other terminal is negative. The positive terminal is slightly larger.
plus is the positive terminal (cathode) minus is the negative terminal (anode)
if non inverting terminal is grounded and input is applied to inverting terminal then as the difference in input voltage should be ideally zero the potential at inverting terminal is also assumed to be zero