4
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
Work it out yourself -the equation is: voltage = current x resistance.
That depends on how much resistance is called for through the engineering, there is tiny resistance (mf) microfared on up huge resistance seen on electrical poles. Your circuit engineering formula dictates the needed resistance or it will just burn or not flow at all, you cannot answer the question without first asking a question..How much resistance do you need. They can be produce for virtually any tolerance.
V = I x R so current I = 1/2 amp. I bet the bulb is rated at 60 W because Watts = Current x Voltage. Where V = voltage (volt) I = current (ampere) R = resistance (ohm) Your question isn't easy to answer. A lamp has two 'resistances': a 'cold' resistance, and a 'hot' resistance. Before it is energised, it is cold, so its resistance is low; when it is energised, it becomes very hot, and its resistance increases significantly. So, the question is whether your '240 ohms' is the cold resistance or the hot resistance. If it is the cold resistance, then a current of 0.5 A will flow through it for a fraction of a second, then its resistance will increase significantly, and the current will fall to a very much smaller value.
An electric current is produced by the change in Magnetic flux over timeRead more: How_do_electromagnets_work
18volts
8x12=96
18 volts
To supply the current needed to develop some horse power to turn over an engine.
12 voltage
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
Work it out yourself -the equation is: voltage = current x resistance.
The resistance needed is1/(the current flowing through the resistance) ohms.
electric current
The battery was invented in 1800 by Alessandro Volta. Batteries were invented in order to power objects that needed an electrical current and also needed to be portable.
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
Voltage, current, or power. You need two out of the three.