First let's calculate the formula mass of SiO2. It is 28.1 + 2(16.0) = 60.1. The amount of SiO2 can be calculated as 6.54/60.1 = 0.109mol. Now in one formula unit of SiO2 there is one Si atom. So, the amount of Si atoms present is 0.109mol. To get the numerical quantity, multiply it by the Avogadro's constant, and we get 0.109 × 6.02 × 10^23 = 6.55 x 10^22 atoms
The mass of silicon is 4 659 g.
number of moles=mass/molar mass =5/(28+32) =0.83 mol
.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms
52.06 grams carbon dioxide (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O) = 1.425 X 10^24 atoms of oxygen --------------------------------------------
10.00 X 10^28 = 1.0 X 1^29 ( always use scientific notation in chemistry ) 1.0 X 10^29 molecules silicon dioxide (1 mole SiO2/6.022 X 10^23)(2 mole O/1 mole SiO2)(16.0 grams/ 1 mole O) = 5.3 X 10^6 grams of oxygen
96,27 g of sand contain 45 g of silicon (if the sand is pure silicon dioxide).
40 grams
The mass of silicon is 4 659 g.
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms
8.5 X 10^-5 grams silicon (1mol Si/28.09g)(6.022 X 10^23/1mol) = 1.8 X 10^18 atoms of silicon
The molar mass of Silicon is 28.09g Therefore if you have 65.6g, you divide that mass by 28.09g. 65.6g/28.09g = 2.34 mols. For atoms, you multiply that number by 6.02 x 1023. So 2.34 x 6.02 x 1023 = 1.41 x 1024.
1.659 [grams] / 47.998 [grams / mol] * 6.02214179(30)×1023 [molecules / mole] * 3 [atoms / molecule]. A bunch.
.250 mole 7.02 ------ 28.09 = .250
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
number of moles=mass/molar mass =5/(28+32) =0.83 mol
.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms