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First let's calculate the formula mass of SiO2. It is 28.1 + 2(16.0) = 60.1. The amount of SiO2 can be calculated as 6.54/60.1 = 0.109mol. Now in one formula unit of SiO2 there is one Si atom. So, the amount of Si atoms present is 0.109mol. To get the numerical quantity, multiply it by the Avogadro's constant, and we get 0.109 × 6.02 × 10^23 = 6.55 x 10^22 atoms

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Q: How many ATOMS of silicon are present in 6.54 grams of silicon dioxide?
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