2.08 moles H2O (2 moles H/1 mole H2O)(1.008 grams H/1 mole H)
= 4.19 grams of hydrogen
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10.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
There are 1.5 moles water in 27 grams
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
I assume you mean 0.5 grams water. 0.5 grams water (1 mole H2O/18.016 grams)(2 moles H/1 mole H2O)(6.022 X 10^23/1 mole H) = 3.3 X 10^22 atoms of hydrogen
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
75 grams water is equal to 4,166 moles.
10.
11
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
There are 1.5 moles water in 27 grams
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
I assume you mean 0.5 grams water. 0.5 grams water (1 mole H2O/18.016 grams)(2 moles H/1 mole H2O)(6.022 X 10^23/1 mole H) = 3.3 X 10^22 atoms of hydrogen
Answer: 16 g of oxygen and 2 g of hydrogen.
180 grams of water is 10 moles of water.
54,0 grams of water is equivalent to 3 moles.
Balanced equation. 2H2 + O2 --> 2H2O 5 moles H2 (2 moles H2O/2 mole H2)(18.016 grams/1 mole H2O) = 90 grams of water ===============