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Each of the nitrogen atoms in N2 needs three electrons, for a total of six.
Nitrogen's position on the periodic table means it is 3 electrons short of the stable noble gas configuration on Neon. If two Nitrogen atoms mutually share 3 electrons to form a triple bond, each nitrogen will have its required quota of electrons to iso-electronic with Neon and thus be stable.
An octet is 8 electrons- but even 2 electrons are okay for achieving stability. A beryllium atom has 2 shells, with 2 electrons in each shell. Since it is a metal, it will lose electrons instead of gaining them, forming a positively charged ion. This means that it will lose both the electrons in its outermost shell, leaving it with a single shell containing 2 electrons. So, basically beryllium loses 2 to electrons to form a stable duet with a charge of 2+! Hope this helped you (:
As you go from left to right on the periodic table, the atomic number increases, but the principal quantum number (number of shells present) does not. Therefore, as the nuclear charge increases, this increases the amount of energy required to remove an outermost electron (ionization energy). However, as you go down the periodic table, the principal quantum number (number of shells) increases. As more and more shells of electrons are added between the outermost shell and the nucleus, these inner shells contribute a "shielding effect" to the outermost electrons, due to interelectron repulsion, which reduce the ionization energy of an atom, because it acts slightly in opposition to the nuclear charge attracting those electrons.
nitrogen
As Nitrogen (N) have atomic number 7, and electronic configuration is 2,5. therefore N required 3 elecrons to complete their outermost shell or orbital.
8 to make it stable and least reactive.
Each of the nitrogen atoms in N2 needs three electrons, for a total of six.
The atomic number for nitrogen is 7. Neutral nitrogen must have both 7 electrons and 7 protons then. The first 7 orbitals are filled as 1s2 2s2 2p3, which shows us that nitrogen has 5 valence electrons.
This is because of the additional processes required to remove the nitrogen containing portion of the component.
Nitrogen's position on the periodic table means it is 3 electrons short of the stable noble gas configuration on Neon. If two Nitrogen atoms mutually share 3 electrons to form a triple bond, each nitrogen will have its required quota of electrons to iso-electronic with Neon and thus be stable.
Ionization energy decreases down a group because with each additional period, there is an additional energy level, so the outermost electrons are farther away from the positive charge of the nucleus, so they are not held as tightly. The further away the valence electrons are from the nucleus, the less energy is required to remove an electron, so the ionization energy decreases.
Nitrogen's position on the periodic table means it is 3 electrons short of the stable noble gas configuration on Neon. If two Nitrogen atoms mutually share 3 electrons to form a triple bond, each nitrogen will have its required quota of electrons to iso-electronic with Neon and thus be stable. Add: Nitrogen atoms have five valence electrons. Two of the valence electrons form a lone pair, and the other three electrons are unpaired. Nitrogen atoms bond with one another by each sharing its three unpaired electrons with the other. This gives each of them six paired electrons, plus the two lone pairs of electrons on each nitrogen atom, which all together forms an octet for each nitrogen atom. An octet is a noble gas configuration, which makes the N2 molecule stable. The lewis dot diagram for an N2 molecule is :N:::N: .
Though the no. of valence electrons remain same in a group,but the distance between the nucleus and outermost shell increases as we move down the group and hence lesser energy is required to release the valence electron.
A pressure regulator is required on a nitrogen tank.
An octet is 8 electrons- but even 2 electrons are okay for achieving stability. A beryllium atom has 2 shells, with 2 electrons in each shell. Since it is a metal, it will lose electrons instead of gaining them, forming a positively charged ion. This means that it will lose both the electrons in its outermost shell, leaving it with a single shell containing 2 electrons. So, basically beryllium loses 2 to electrons to form a stable duet with a charge of 2+! Hope this helped you (:
Valency is the number of electrons to reach the stable number of 8 electrons in its outer shell. Electrically neutral chlorine has 7 electrons its outermost shell. This means that a single bond, where two electron orbitals overlap is required to form the stable element allotrope, therefore two atoms of chlorine are needed.