12.54 (g O2) / 2*15.99 (g/mol O2) = 0.3921 mol O2 -->
0.3921 (mol O2) * 6.022*1023 (molecules O2)/(molO2) =
= 2.361*1023 molecules O2
= 4.723*1023 atoms O
150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2
The number of oxygen atoms is 0,188.10e23.
Cu2 should be '2Cu' ( two uncombined atoms of copper.) O2- should be 'O2; ( 2 combined atoms of oxygen). When heated 2Cu(s) + O2(g) = 2CuO(s) CuO is copper oxide and appears as a black solid.
The number of atoms of lead is 6,68.10e23.
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
The answer is 0,068 mol (for O not for O2).
16.0 lbs = 7,257 g of O2 Oxygen exists in the gas form as 02 7,257g O2 * 1 mol O2/ 32 g * 2 mol O / 1 mol O2 * 6.022x10^23 atoms/mol = 2.73E26 atoms of O
150.0 g O2 x 1 mole O2/32 g O2 = 4.688 moles O2
One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.
The number of oxygen atoms is 0,188.10e23.
Cu2 should be '2Cu' ( two uncombined atoms of copper.) O2- should be 'O2; ( 2 combined atoms of oxygen). When heated 2Cu(s) + O2(g) = 2CuO(s) CuO is copper oxide and appears as a black solid.
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
The number of atoms of lead is 6,68.10e23.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
1 mole O2 weighs 32 gso 64 g O2 is 2 mol O2 gaswhich has 2 X 6.022 X 1023 = 1.2066 X 1024 molecules of O2