So, 70.620 g of rhenium will have 2.284 x 1023atoms.
To determine the number of atoms in a given mass of an element, you need to know the molar mass of that element. The molar mass of rhenium (Re) is 186.207 g/mol. To find the number of atoms in 70.620 g of rhenium, divide the given mass by the molar mass, and then multiply by Avogadro's number (6.022 x 10^23). This gives approximately 1.590 x 10^23 atoms of rhenium.
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
5 g of sulfur contain 0,94.10e23 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
The number of atoms is 28,099.10e23.
25.1
186.207 g/mol
The number of atoms of lead is 6,68.10e23.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
6,687.1023 chlorine atoms
27,30.10e23 atoms
The number of atoms of lead is 6,68.10e23.
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
G. W. Leddicotte has written: 'The radiochemistry of platinum' -- subject(s): Platinum, Radiochemistry 'The radiochemistry of rhenium' -- subject(s): Radiochemistry, Rhenium 'The radiochemistry of sulfur' -- subject(s): Sulphur
156,86.1020 atoms of uranium in 6,2 g uranium
5 g of sulfur contain 0,94.10e23 atoms.
The answer is 3.32*10^23 atoms