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48,177 134 32.1023 atoms
2
26,4 g iridium is equal to 0,137 mol.
The chemical formula of propane is C3H8; 11 atoms are present in the molecule.
No
4 oxygen atoms are present
48,177 134 32.1023 atoms
two atoms
481,7713432.1023 atoms
The total no. of atoms present in C12H22O11 is 45.
The number of atoms is indicated by coefficients.
2
26,4 g iridium is equal to 0,137 mol.
4 oxyzen atoms
The chemical formula of propane is C3H8; 11 atoms are present in the molecule.
The number of atoms is 33.
48,177 134 32.1023 atoms